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Black_prince [1.1K]
3 years ago
10

Reduce to lowest terms 3m^2-3n^2/6m-6n Options A. -m-n/2 B. m-n/2 C. m+n/2

Mathematics
2 answers:
kenny6666 [7]3 years ago
4 0
Your answer is C because you have to simply the problem and you end up getting m+n/2
RSB [31]3 years ago
3 0
Your answer B slime ball
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If the graph of the function moves to the right two units what is the new vertex of the function
Allisa [31]

Answer:

Let's talk through this a one step at a time.

*Since f(x) is concave-up with its vertex on the x-axis, we know f(x) ≥ 0.

*We also know that when we shift a function's domain by a positive number, we shift the function left and when we shift a function's domain by a negative number, we shift the function right. So f(x-5) is f(x) shifted to the right by 5.

*At this point, f(x-5) has its vertex at (5,0).

*When we negate f(x-5), the parabola becomes concave down yet the vertex remains at (5,0). Now we're at -f(x-5). At this point we have -f(x-5)≤0 with a range (-∞,0]

*If we add 2 to create g(x)=2-f(x-5), then we have a concave down parabola with its vertex shifted up by 2, at (5,2). So, g(x) is concave down with its vertex at (5,2). Hence

5 0
3 years ago
14) The number of students at LAMS is 1872 students. The ratio of girls to
bogdanovich [222]

Answer:

310

Step-by-step explanation:

total no.of students=1872

ratio of boys to girls=7:5

sum of ratio=total of students

12/12=1872

7/12=?

7/12*1872/1=1092which is the number of girls

1872-1092=780which is the number of boys

difference =1092-780= 310

7 0
3 years ago
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
3 years ago
Read 2 more answers
Write a value-returning recursive function that computes the sum of the digits in a given positive int argument. for example, if
mars1129 [50]
244556
2+4+4+5+5+6=26
5 0
3 years ago
What is the probability of getting either a nine or an ace when drawing a single card from a deck of 52​ cards?
Flura [38]

probability of drawing ace: 4/52 = 1/13

probability of drawing 9: 4/52 = 1/13

probability of drawing ace or 9: 1/13 + 1/13 = 2/13 or ~15.4%

8 0
2 years ago
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