Answer: 5225472000
Step-by-step explanation:
Given : The number of bulls = 6
The number of horses = 10
Since Aidan needs to place them in a line of 16 paddocks, and the bulls cannot be placed in adjacent paddocks .
Also there are two ways to arrange the group pf bulls and horses.
Then , the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks will be :_
Hence, the number of ways Aiden can place the bulls and horses in the paddocks so that no two bulls are paddocks =5225472000
You start at 0 on the unit circle the cos of 0 =1, but at cos 0 there is no angle at all so there is no y value so at cos 0 y=0, 180 is the opposite direction of the starting point which is 0 so the x value of cos180= -1 but there is still no upward or downward angle ie.. y value. so the y value = 0 at 0 and 180. answer is 0
<h3>Solution :</h3>
By cross multiply, we get
Therefore, answer is 
If you're trying to say what's 90% of 63, you divide 63 by 10 which is 6.3 then times by 9 which is 56.7
Answer:
The answer is 10m + 7n - 14
Step-by-step explanation:
Q = 7m + 3n
R = 11 - 2m
S = n + 5
T = -m - 3n + 8
[Q - R] + [S - T] is
[ 7m + 3n - (11 - 2m) ] + [ n + 5 - ( - m - 3n+8)]
Solve the terms in the bracket first
That's
( 7m + 3n - 11 + 2m ) + ( n + 5 + m + 3n - 8)
( 9m + 3n - 11 ) + ( m + 4n - 3)
<u>Remove the brackets</u>
That's
9m + 3n - 11 + m + 4n - 3
<u>Group like terms</u>
9m + m + 3n + 4n - 11 - 3
The final answer is
<h3>
10m + 7n - 14</h3>
Hope this helps you
