How do linear, quadratic, and exponential functions compare?
Answer:
How can all the solutions to an equation in two variables be represented?
<u><em>The solution to a system of linear equations in two variables is any ordered pair x,y which satisfies each equation independently. U can Graph, solutions are points at which the lines intersect.</em></u>
<u><em /></u>
<u><em>How can all the solutions to an equation in two variables be represented?</em></u>
<u><em>you can solve it by Iterative method and Newton Raphson's method.</em></u>
<u><em /></u>
<u><em>How are solutions to a system of nonlinear equations found?
</em></u>
Solve the linear equation for one variable.
Substitute the value of the variable into the nonlinear equation.
Solve the nonlinear equation for the variable.
Substitute the solution(s) into either equation to solve for the other variable.
<u><em>
</em></u>
<u><em>How can solutions to a system of nonlinear equations be approximated? U can find the solutions to a system of nonlinear equations by finding the points of intersection. The points of intersection give us an x value and a y value. Using the example system of nonlinear equations, let's look at how u can find approximate solutions.</em></u>
If you know the base and area of the triangle, you can divide the base by 2, then divide that by the area to find the height. To find the height of an equilateral triangle, use the Pythagorean Theorem, a^2 + b^2 = c^2.
b - 10 = 7
Take 10 to the other side.
b = 17
Multiply by 4 to isolate b
b × 4 = 17 × 4
4 and 4 cancels out
b = 68
Answer:
About 67%
Step-by-step explanation:
This is a conditional relative frequency. There are 36 students who are aged 14-17 and 24 of them skip breakfast. Therefore, the answer is 24/36 = 2/3 ≈ 67% (ans)
Answer:
Step-by-step explanation:
Since angles A and E correspond, as well as angles C and F, we can say ...
ΔABC ~ ΔEDF
Then the ratio of side lengths of ΔABC to those of ΔEDF is ...
AC/EF = 6/2 = 3
That means ...
ED/AB = 1/3
ED = AB·(1/3) = 3.3·(1/3) = 1.1
For the remaining sides, we have the relation
3·DF = BC
3·(BC -3.2) = BC
2BC - 9.6 = 0 . . . eliminate parentheses, subtract length BC
BC -4.8 = 0 . . . . . divide by 2
BC = 4.8 . . . . . . . . add 4.8
DF = BC·(1/3) = 1.6
The unknown side lengths are BC = 4.8, DE = 1.1, DF = 1.6.
