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3 years ago

Find four consecutive integers such that the sum of the second and fourth is 132

Mathematics

1 answer:

Ulleksa [173]3 years ago

7 0

Remark

As long as the representation shows the numbers come one after another, you can get x to be anything.

Givens

x Can be the second number

x - 1 Can be the first number

x + 1 Can be the third number

x + 2 Can be the fourth number

Equation

x + x + 2= 132

Solution

2x + 2 = 132

2x = 130

x = 65

So the 4 numbers are 64 65 66 67

Check

The second and fourth numbers added together = 65 + 67 = 132

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Answer:

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Part 2) The area of rectangle is equal to 32 square units

Step-by-step explanation:

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we know that

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where

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W is the width of rectangle

we have

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Plot the figure to better understand the problem

using a graphing tool

see the attached figure

Remember that in a rectangle opposite sides are congruent and the measure of each interior angle is equal to 90 degrees

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the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance FG

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substitute the values

$d=\sqrt{(5-5)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

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step 2

Find the distance RF

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substitute the values

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step 3

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we have

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substitute

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Part 2) Find the area of rectangle FROG

we know that

The area of rectangle is equal to

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we have

$FG=RO=L=8\ units\\RF=OG=W=4\ units$

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