<span>Let us start with the schnauzers, the easiest one to imagine. Let us assume that there were x number of schnauzers.
Scottie's are 3 more than schnauzers. So their number is x+3
Wire haired terriers are 5 less than twice the number of schnauzers.
So their number is 2x -5 (2x for twice the number of schnauzers)
Now add all these numbers.
That is x + x+3 + 2x-5 = 4x -2
The total number of dogs, 78, is given in the question
Now we know that 4x -2 =78
4x = 78 +2
= 80
Therefore x = 80/4
= 20.
So there were 20 schnauzers, 23 Scottie’s and 35 wire haired terriers</span>
Shaded part means the yellow part
- The two sets are S and Y.
- The centre intersection part is A

- All the areas occupied by both sets is AUB .
Rest part :-

Answer:

Step-by-step explanation:
To find:
The value of
= ?
Solution:
Kindly consider the equilateral
as attached in the answer area.
Let the side of triangle =
units
Let us draw the perpendicular from vertex A to side BC.
It will divide the side BC in two equal parts.
i.e. BD = DC = 
Using Pythagorean Theorem in
:

Side AD = 
Using Trigonometric ratio:


Putting the values of AD and BD:

Answer:

Step-by-step explanation:

The graph is shifted 3 units to the right


Answer:
to do this we have to divide 43 by 83
0.51807228915
so the frequency is about 51.8%