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neonofarm [45]
3 years ago
6

Which represents the inverse of the function f(x)=4x

Mathematics
1 answer:
liraira [26]3 years ago
5 0
The answer will be F^-1= x/4
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X^2+2x-15/x=x-1/2+x-1/x​
ZanzabumX [31]

Answer:

x=2.11872822

Step-by-step explanation:

7 0
3 years ago
Ellie uses 12.5 pounds of potatoes bto make mashed potatoes. She uses one tenths as many pounds of butter as potatoes how many p
In-s [12.5K]

Answer:

1.25 Pounds were used for butter.

Step-by-step explanation:

6 0
3 years ago
5. Can someone explain how to solve this?
zhannawk [14.2K]

Answer:

AC = 5 cm

BD = 12.5 cm (3 sf) [or 2 × root 39]

BE = 6.93 cm (3 sf) [or 4 × root 3]

Step-by-step explanation:

CE = 8cm [CE is radius of circle]

AC + 3 = 8

<u>A</u><u>C</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>c</u><u>m</u>

BC = 8cm [BC is a radius of circle]

(AC)^2 + (AB)^2 = (BC)^2 [Pythagoras theorem]

25 + (AB)^2 = 64

AB = 6.2450 cm (5 sf) [or root 39]

BD = 2(BA)

= 2(6.2450)

<u>B</u><u>D</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u><u>.</u><u>5</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>2</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>9</u><u>]</u>

(BA)^2 + (AE)^2 = (BE)^2 [Pythagoras theorem]

39 + 9 = (BE)^2

<u>B</u><u>E</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>9</u><u>3</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>4</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>]</u>

6 0
3 years ago
Type the correct answer in the box. Use numerals Instead of words. If necessary, use / for the fraction bar.
Zielflug [23.3K]

Using an exponential function, it is found that the value of David's Investment will be at least $415 after a period of 20 years.

<h3>What is an exponential function?</h3>

An increasing exponential function is modeled by:

A(t) = A(0)(1 + r)^t

In which:

  • A(0) is the initial value.
  • r is the growth rate, as a decimal.

In this problem, the initial value and the growth rate for his investment are given by:

A(0) = 230, r = 0.03.

Hence, the value after t years is given by:

A(t) = 230(1.03)^t

Then, the value will be of at least $415 when:

A(t) \geq 415

230(1.03)^t \geq 415

(1.03)^t \geq \frac{415}{230}

\log{(1.03)^t} \geq \log{\frac{415}{230}}

t\log{1.03} \geq \log{\frac{415}{230}}

t \geq \frac{\log{\frac{415}{230}}}{\log{1.03}}

t \geq 20

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

4 0
2 years ago
The amount people who pay for cell phone service varies quite a bit, but the mean
melamori03 [73]

Answer:

a) The mean is $55 and the standard deviation is $0.6957

b) The shape of the sampling distribution of x is approximately normal.

c) 0.0749 = 7.49% probability that the average cell phone service paid by the sample of cell phone users will exceed $56.

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

Mean of the distribution: 55

Standard deviation of the distribution: 22

Sample of 1000.

This means that:

\mu = 55, \sigma = 22, n = 1000

Part A: What are the mean and standard deviation of the sample distribution of X?

By the Central Limit Theorem, the mean is 55 and the standard deviation is s = \frac{22}{\sqrt{1000}} = 0.6957.

Part B: What is the shape of the sampling distribution of x?

By the Central Limit Theorem, the shape of the sampling distribution of x is approximately normal.

Part C: What is the probability that the average cell phone service paid by the sample of cell phone users will exceed $56?

This is 1 subtracted by the pvalue of Z when X = 56. So:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{56 - 55}{0.6957}

Z = 1.44

Z = 1.44 has a pvalue of 0.9251

1 - 0.9251 = 0.0749

0.0749 = 7.49% probability that the average cell phone service paid by the sample of cell phone users will exceed $56.

7 0
3 years ago
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