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julia-pushkina [17]
3 years ago
5

How do u write 5(2x - 1) in a distributive property

Mathematics
1 answer:
Nookie1986 [14]3 years ago
5 0

Answer:

5(2x-1) = 5(2x) - 5(1)

Step-by-step explanation:

The distributive property states that multiplying a sum or difference of two terms by a number is equal to multiplying the same number with each term of the sum or difference separately and then adding the products.

It can be written as:

a(b+c) = ab + ac

or

a(b-c) = ab - ac

So, for the given question,

=>5(2x-1) = 5(2x) - 5(1)

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f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

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