(Question 1)

A fence is 10 feet tall. A stick leans against the fence as shown. What is the length of the stick?

Vitek1552 [10]

The answer should be 22 1/2 ft

5 0

2 years ago

4·(4+32+42) please help fast

wariber [46]

PLEASE ANSWER BOTH AS FAST AS POSSIBLE PLEASE HELP HELP ILL MARK BRAINLEST!!!!! PLEASE ANSWER BOTH AS FAST AS POSSIBLE PLEASE HELP HELP ILL MARK BRAINLEST!!!!! PLEASE ANSWER BOTH AS FAST AS POSSIBLE PLEASE HELP HELP ILL MARK BRAINLEST!!!!! PLEASE ANSWER BOTH AS FAST AS POSSIBLE PLEASE HELP HELP ILL MARK BRAINLEST!!!!! PLEASE ANSWER BOTH AS FAST AS POSSIBLE PLEASE HELP HELP ILL MARK BRAINLEST!!!!!

7 0

3 years ago

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Consider the following differential equation to be solved by undetermined coefficients. y(4) − 2y''' + y'' = ex + 1 Write the gi

kompoz [17]

Answer:

The general solution is

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2}$

Step-by-step explanation:

Step :1:-

Given differential equation y(4) − 2y''' + y'' = e^x + 1

The differential operator form of the given differential equation

$(D^4 -2D^3+D^2)y = e^x+1$

comparing f(D)y = e^ x+1

The auxiliary equation (A.E) f(m) = 0

$m^4 -2m^3+m^2 = 0$

$m^2(m^2 -2m+1) = 0$

$(m^2 -2m+1) this is the expansion of (a-b)^2$

$m^2 =0 and (m-1)^2 =0$

The roots are m=0,0 and m =1,1

complementary function is $y_{c} = (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x$

<u>Step 2</u>:-

The particular equation is $\frac{1}{f(D)} Q$

P.I = $\frac{1}{D^2(D-1)^2} e^x+1$

P.I = $\frac{1}{D^2(D-1)^2} e^x+\frac{1}{D^2(D-1)^2}e^{0x}$

P.I = $I_{1} +I_{2}$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x + \frac{1}{D^{2} } e^{0x}$

$\frac{1}{D} means integration$

$\frac{1}{D^2} (\frac{x^2}{2!} )e^x = \frac{1}{2D} \int\limits {x^2e^x} \, dx$

applying in integration u v formula

$\int\limits {uv} \, dx = u\int\limits {v} \, dx - \int\limits ({u^{l}\int\limits{v} \, dx } )\, dx$

$I_{1}$ = $\frac{1}{D^2(D-1)^2} e^x$

$\frac{1}{2D} (e^x(x^2)-e^x(2x)+e^x(2))$

$\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

$I_{2}$ $= \frac{1}{D^2(D-1)^2}e^{0x}$

$\frac{1}{D} \int\limits {1} \, dx= \frac{1}{D} x$

again integration $\frac{1}{D} x = \frac{x^2}{2!}$

The general solution is $y = y_{C} +y_{P}$

$y= (C_{1}+C_{1}x) e^0x+(C_{3}+C_{4}x) e^x +\frac{1}{2} (e^x(x^2-2x+2)-e^x(2(x-1)+e^x(2))$

+ $\frac{x^2}{2!}$

3 0

3 years ago

I will give brainliest here is the picture I need this ASAP

julia-pushkina [17]

Answer:

Step-by-step explanation:

Start with our equation:

s=2(lw+wh+hl)

Plug in our values for l, w, and h:

s=2(12*9+9*2+2*12)

Simplify:

s=300

7 0

2 years ago

I like risking my points for hard homework

ELEN [110]

Answer:

The triangle and the square have the same area because they both have four squares

Step-by-step explanation:

The square has four that are easily shown but the triangle has one full one but when two are split together like some of them when you put the two together they equal one whole.

Have a wonderful day/night/afternoon

7 0

1 year ago

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