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Anika [276]
4 years ago
12

When constructing inscribed polygons and perpendicular lines how are the steps similar

Mathematics
1 answer:
bagirrra123 [75]4 years ago
8 0
When constructing inscribed polygons and perpendicular lines, how are the steps similar?
<span>There are no similarities.</span>
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the cosine of an angle is the ratio of the length of the leg_______that angle to the length of the _________.?help please
krok68 [10]

Answer:

The cosine of an angle is the ratio of the length of the leg adjacent to the angle to the length of the hypotenuse.

Step-by-step explanation:

  • In a right angled triangle, the cosine of an angle is the length of the adjacent side divided by the length of the hypotenuse.
  • Also it is the sine of the complementary angle.
  • The abbreviation is cos
  • The longest side of the triangle is called the hypotenuse,
  • The side opposite the angle theta is called the opposite side,
  • The third side is called the adjacent side.
  • Therefore, cos(\theta) = \frac{adjacent}{ hypotenuse}

6 0
3 years ago
What comes after 95,000
Bess [88]
95,001

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3 years ago
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Two patrol boats leave Cape May at the same time, the same speed, but on different bearings. One has bearing 41°45
VMariaS [17]

Based on the information given, the computation shows that the distance between them is 2.47 miles.

<h3>Solving the distance.</h3>

Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.

The other has bearing 59°13'. This will be:

= 59° + (13/60) = 59° + 0.22 = 59.22°.

The difference of the angles will be:

= 59.22° - 41.75°

= 17.47°

Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:

c² = a² + b² - 2ab cos 17.47°

c² = 20² + 20² - (2 × 20 × 20 × 0.19)

c² = 6.07459

c = 2.47

Learn more about distance on:

brainly.com/question/2854969

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2 years ago
A 5-gallon jug of cleaning solution contains 6% bleach. How much pure water should be added to it to dilute to 4% bleach?
mihalych1998 [28]
Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach?  well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.

if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.

the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.

\bf \begin{array}{lcccl}&#10;&\stackrel{gallons}{quantity}&\stackrel{\textit{\% of bleach}}{amount}&\stackrel{\textit{gallons of bleach}}{amount}\\&#10;&------&------&------\\&#10;\textit{pure water}&x&0.00&0x\\&#10;\textit{6\% solution}&5&0.06&0.3\\&#10;-----&------&------&------\\&#10;mixture&y&0.04&0.04y&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+5=\boxed{y}\\&#10;0x+0.3=0.04y\\&#10;---------\\&#10;0.3=0.04\left( \boxed{x+5} \right)&#10;\end{cases}&#10;\\\\\\&#10;0.3=0.04x+0.2\implies 0.1=0.04x\implies \cfrac{0.1}{0.04}=x\implies 2.5=x
3 0
3 years ago
If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?
melamori03 [73]
\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$4432.37\\&#10;P=\textit{original amount deposited}\to &\$3000\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &8&#10;\end{cases}

\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8&#10;\\\\\\&#10;\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r&#10;\\\\\\&#10;0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086&#10;\\\\\\&#10;r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}
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4 years ago
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