Answer:
5a^4+a^2b−6b^2
Step-by-step explanation:
1. Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.
5a^4+6a^2b−5ba^2−6b^2
2. Collect like terms.
5a^4+(6a^2b−5a^2b)−6b^2
3. Simplify.
5a^4+a^2b−6b^2
A. 5x and 2y
B. 3 and x
C. 5x and x
D. 4
Answer:
We need to use
Step-by-step explanation:
We have to use the equation for passing through the points known as
y2-y1/x2-x1
-1-3/0-5= -4/-5
the answer is 4/5
decimal: 0.8
The largest possible volume of the given box is; 96.28 ft³
<h3>How to maximize volume of a box?</h3>
Let b be the length and the width of the base (length and width are the same since the base is square).
Let h be the height of the box.
The surface area of the box is;
S = b² + 4bh
We are given S = 100 ft². Thus;
b² + 4bh = 100
h = (100 - b²)/4b
Volume of the box in terms of b will be;
V(b) = b²h = b² * (100 - b²)/4b
V(b) = 25b - b³/4
The volume is maximum when dV/db = 0. Thus;
dV/db = 25 - 3b²/4
25 - 3b²/4 = 0
√(100/3) = b
b = 5.77 ft
Thus;
h = (100 - (√(100/3)²)/4(5.77)
h = 2.8885 ft
Thus;
Largest volume = [√(100/3)]² * 2.8885
Largest Volume = 96.28 ft³
Read more about Maximizing Volume at; brainly.com/question/1869299
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That’s the equation for pi, but the simplified fraction is 22/3 (please mark brainliest)
