The first false statement in the proof as it stands is in Line 5, where it is claimed that a line of length 2.83 is congruent to a line of length 4.47. This mistake cannot be corrected by adding lines to the proof.
_____
The first erroneous tactical move is in Line 4, where the length of DE is computed, rather than the length of FD. This mistake can be corrected by adding lines to the proof.
A correct SAS proof would use segment FD in Line 4, so it could be argued that the first mistake is there.
The correct answer is B. 2.3.
For us to know the equivalent decimals of a fraction, you have to use the numerator as the dividend, and the denominator will be your divisor.
The equation will be:
2 + ( 1 / 3 )
2 + (0.33333333)
= 2.333333
If you'll have it rounded off, you'll get the answer 2.3.
Answer: Third option.
Step-by-step explanation:
By definition, Exponential functions have the following form:
Where "b" is the base (
and 
), "a" is a coefficient (
) and "x" is the exponent.
It is importat to remember that the "Zero exponent rule" states that any base with an exponent of 0 is equal to 1.
Then, for an input value 0 (
) the output value (value of "y") of the set of ordered pairs that could be generated by an exponential function must be 1 (
).
You can observe in the Third option shown in the image that when ,
Therefore, the set of ordered pairs that could be generated by an exponential function is the set shown in the Third option.
<span>B) y = -3x3
</span>-----------------------------------
Answer:
This is 0.14 to the nearest hundredth
Step-by-step explanation:
Firstly we list the parameters;
Drive to school = 40
Take the bus = 50
Walk = 10
Sophomore = 30
Junior = 35
Senior = 35
Total number of students in sample is 100
Let W be the event that a student walked to school
So P(w) = 10/100 = 0.1
Let S be the event that a student is a senior
P(S) = 35/100 = 0.35
The probability we want to calculate can be said to be;
Probability that a student walked to school given that he is a senior
This can be represented and calculated as follows;
P( w| s) = P( w n s) / P(s)
w n s is the probability that a student walked to school and he is a senior
We need to know the number of seniors who walked to school
From the table, this is 5/100 = 0.05
So the Conditional probability is as follows;
P(W | S ) = 0.05/0.35 = 0.1429
To the nearest hundredth, that is 0.14
