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Kazeer [188]
3 years ago
6

1) The cost of constructing a path 5 m broad inside the boundary of a square lawn at Rs 36.25 per sq. metre is Rs 90625. What is

the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre?​
Mathematics
1 answer:
Svetach [21]3 years ago
3 0

Let , side lawn is a.

Area of boundary is :

A=4\times5\times a\\\\A=20a\ m^2

Now, total cost is given by :

T=20a\times 36.25\\\\90625=725a\\\\a=125\ m

Area left is :

A'=a^2-20a\\\\A'=125^2-20\times 125\ m^2\\\\A'=13125\ m^2

Price to empty space with turfs is :

P=A'\times 20\\\\P=13125\times 20\\\\P=262500

Therefore, the cost of covering the empty space with turfs at the rate of Rs 20 per sq. metre is Rs 262500.

Hence, this is the required solution.

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Lif a/b =⅔ find the value of 2a²+3b²/a²+b²<br>​
Contact [7]

Answer:

95/4

Step-by-step explanation:

Given,

a/b =2/3

Therefore, 2a²+3b²/a²+b² = ?

We get,

a/b = 2/3

So, we can write

a = 2 and b = 3

Now,

2×(2)² + 3×(3)²/(2)² + (3)² [Putting the values of a and b]

= 2×4 + 3×9/4 + 9

= 8 +27/4 + 9

= (32+27+36)/4 [ Taking L.C.M, we get 4]

= 95/4

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3 years ago
Find the difference between (2x-5) and (3-9x)
BARSIC [14]
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This net can be folded to make a square pyramid. what is the surface area of the pyramid
givi [52]

Answer:  

85in^2

Step-by-step explanation:

to find the surface area we need to find the followng areas:  

  • area of the square  
  • area of a triangle and multiply it by 4 (because there are 4 triangles)

And once we have those areas, we add them to find the surface area.

Area of the square:

the formula to find the area of a square is:

a_{square}=l^2

where l is the length of the side: l=5in

thus the area of the square is:

a_{square}=(5in)^2

a_{square}=25in^2

Area of the triangles:

the are of 1 triangle is given by

a_{triangle} =\frac{b*h}{2}

where b is the base of the triangle: b=5in (the base of the triangle is the side of the square)

and h is the height of the triangle: h=6in

thus, the area of 1 triangle is:

a_{triangle} =\frac{(5in)*(6in)}{2}

a_{triangle} =\frac{30in^2}{2}

a_{triangle} =15in^2

the area of the 4 triangles is (we multiply by 4):

a_{4-triangles}=4(15in^2)

a_{4-triangles}=60in^2

finally we add the area of the square and the area of the 4 triangles to find the total surface area:

Surface=25in^2+60in^2

Surface=85in^2

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Interest after 1 year:
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