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umka21 [38]
3 years ago
13

Which inequality represents the following sentence.

Mathematics
2 answers:
maria [59]3 years ago
6 0
A.
x - 8 \geqslant 20
garri49 [273]3 years ago
6 0

Answer:

the answer is A

Step-by-step explanation:


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What is the ratio of 3ft to 5in
shtirl [24]
Im not that sure but i think it is 5
8 0
3 years ago
Image point B'(4, -8) was transformed using the translation (x-2, y + 3). What were the coordinates of B?
DaniilM [7]

Answer:

B(6 , -11)

Step-by-step explanation:

(x-2 , y+3)  = (4 , -8)

Compare the x & y co ordinates

x - 2 = 4   ; y + 3 = -8

x = 4 +2  ; y = -8 - 3

x = 6      ; y = -11

B(6 , -11)

8 0
3 years ago
for each of the following find, if possible, a whole number that makes the equation true. a. 3+ z=12 b. 36 = 18 + 3 •Z
Basile [38]

Answer:

a. 9

b. 6

Step-by-step explanation:

a. z=12 - 3= 9

b. (36 - 18)/3= Z

6 0
3 years ago
If x+y=5,x-y=4,find the value of x²-y²​
inysia [295]

Answer:

20

Step-by-step explanation:

→ First find the value of x and y

x + y = 5

x - y = 4

→ Add the equations to cancel out the y's

2x = 9

→ Divide both sides by 2 to find the value of x

x = 4.5

→ Substitute x = 4.5 back into x - y = 4 to find the value of y

4.5 - y = 4

→ Minus 4.5 from both sides to isolate -y

-y = -0.5

→ Multiply everything by -1

y = 0.5

→ Substitute x = 4.5 and y = 0.5 into x² - y²

4.5² - 0.5² = 20.25 - 0.25 = 20

4 0
3 years ago
Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.
melamori03 [73]

Answer:

6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs AB=3, BC=4, and AC=5. The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base b and height h is given by A=\frac{1}{2}bh. Therefore, the area of this right triangle is:

A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}

The other triangle is a bit trickier. Triangle \triangle ADC is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by:

A=\sqrt{s(s-a)(s-b)(s-c)}, where a, b, and c are three sides of the triangle and s is the semi-perimeter (s=\frac{a+b+c}{2}).

The semi-perimeter, s, is:

s=\frac{5+5+4}{2}=\frac{14}{2}=7

Therefore, the area of the isosceles triangle is:

A=\sqrt{7(7-5)(7-5)(7-4)},\\A=\sqrt{7\cdot 2\cdot 2\cdot 3},\\A=\sqrt{84}, \\A=2\sqrt{21}\:\mathrm{cm^2}

Thus, the area of the quadrilateral is:

6\:\mathrm{cm^2}+2\sqrt{21}\:\mathrm{cm^2}=\boxed{6+2\sqrt{21}\:\mathrm{cm^2}}

4 0
3 years ago
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