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Margarita [4]
3 years ago
15

What is the area of this figure? I give brainliest and thanks :)

Mathematics
2 answers:
Alex777 [14]3 years ago
6 0

Answer:

591 square cm

Step-by-step explanation:

25 times 23 =575

4 times 4 =16

575 plus 16=591

sattari [20]3 years ago
6 0

Answer:

591

Step-by-step explanation:

23x25=575+(4x4)=591

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Dy/dxif y = 4x3 + 3x2 + 2
DIA [1.3K]
The function is 

                                \displaystyle{ y=4x^3+3x^2+2.

We recall that the derivative of each monomial ax^b is a\cdot b\cdot x^{b-1}, and the derivative of a constant (function) is 0.

According to this:

\frac{d}{dx}(4x^3+3x^2+2)=4\cdot 3\cdot x^2 + 3\cdot 2\cdot x+0 =12x^2+6x.


Answer: 12x^2+6x
7 0
3 years ago
To get to school, Grayson usually walks 1.5 miles west and 0.8 miles north on the sidewalks. Because he is in a hurry, he has de
Alex17521 [72]

Answer:

Grayson has to walk 1.7 miles across the field.

Step-by-step explanation:

We have drawn the diagram for your reference.

Given:

Grayson usually walks 1.5 miles west on the side walks

According to Diagram we can say;

CA = 1.5 miles

Also Given:

Grayson also walks 0.8 miles north on the sidewalks

So According to Diagram we can say;

BA =0.8 miles

Now we need to find number of miles Grayson have to walk across the field.

According to diagram we can say;

We have to find CA.

Assuming the diagram  to be right angled triangle.

We can find CA using Pythagoras theorem.

{CA}^2 = {CB}^2+{BA}^2

Substituting the given values we get;

{CA}^2 =1.5^2+0.8^2 = 2.25 +0.64 =2.89

Taking square root on both side we get;

\sqrt{{CA}^2} = \sqrt{2.89} \\\\CA = 1.7 \ mi

Hence Grayson has to walk 1.7 miles across the field.

4 0
3 years ago
If f(x)=\sqrt(3x+2) , what is the equation for f-1(x)
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If f(x)=\sqrt{3x+2} then f^{-1}(x)=(3x+2)^2.

Hope this helps.

4 0
4 years ago
a building casts a shadow of 95 feet long. if a yardstick casts a shadow of 5 feet, how tall is the building?
Nana76 [90]
The building will be 90 ft. long
8 0
3 years ago
Write a pair of numbers such that the value of the 7 in the first number is 1000 times the value of the 7 in the second number,
telo118 [61]

<u>Answer-</u>

As infinitely many such possible number pairs can be formed, one of the instances of such pair would be (37000 and 307).

<u>Solution-</u>

Suppose the former one is aaaaa and the later one is bbbbb.

The value of 7 in the former is 1000 times greater than in the later, so let's make it 7000 and 7.

Then the numbers will be in the following form,

a7aaa and bbbb7

Again, the value of 3 in the former is 100 times greater than in the later.

Then the numbers will be in the following form,

37aaa and bb3bb7

Substituting all the a's and b's by 0,

we get, 37000 and 307 is a possible set. Replacing 0 with any number from 1-9, will yield another number pair which will satisfy the conditions.


6 0
3 years ago
Read 2 more answers
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