Let us take number of $5 bills = x and
number of $10 bills = y.
Give that "number of $10 bills is twice the number of $5 bills".
So, y is twice of x,
We can setup an equation.
y= 2x ............................... equation(1)
Total value of all bills = $125.
We can setup another equation,
5*(number of $5 bills) + 10*(number of $10 bills) =125.
5(x) +10(y) = 125 ................................... equation(2)
Plugging y=2x in equation(2), we get
5(x) +10(2x) = 125 .
5x+20x = 125.
Adding like terms
25x = 125
Dividing both sides by 25.
25x /25 = 125/25
x= 5.
Plugging x=5 in first equation, we get
y= 2(5) = 10.
Therefore, number of number of $5 bills=5 bills and number of $10 bills = 10 bills.
4x² + 3x + 9
x - 2|4x³ - 5x² + 3x - 1
4x³ - 8x²
3x² + 3x
3x³ - 6x
9x - 1
9x - 18
17
The remainder of the problem is D.
Answer:
A
Step-by-step explanation:
Its a simple equation.
Distribute the 5 into the parenthesis:
2
a
−
5
a
−
5
Simplify:
Answer:
it is so unclear to say . If any more information is given, then only it can be answered. I don't think 196 is so special to be classified.