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3 years ago

Convert 1.43 g/mL to the unit g/m3.

1 answer:

8 0

1430000 is the answer to Converting 1.43 g/mL to the unit g/m3 Also, 1 ml = 1cm3 = 1E-6 m3 
1.43/ml= 1.43E-6 g/m3 (1.43 x 10-6 g/m3) and 1.43 x 106 (grams / cubic meter) =0.15158 kg / m3

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Please tell me how can i find x without calculator ?

gtnhenbr [62]

I hope this helps you

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3 years ago

Question 5 (1 point)

11Alexandr11 [23.1K]

Answer:

Hi there!

The answer to this question is (B) 4

Step-by-step explanation:

Using the order of operations, you first solve what it is inside of the parenthesis, which in this case is (4-2), that equals to 2.

then you need to figure out what multiply by 2 gets 8. Out of all the answer choice (B) fits perfectly.

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3 years ago

Find an equivalent system of equations for the following system: 3x + 3y = 0 −4x + 4y = −8

Rama09 [41]

Answer:

Answer:

3x + 3y = 0

7x - y = 8

Step-by-step explanation:

3 0

3 years ago

Please help (-0.5)/(-0.5 ) -50/(-0.5 )

Kipish [7]

If you would like to solve (- 0.5) / (- 0.5) and - 50 / (- 0.5), you can do this using the following few steps:

(- 0.5) / (- 0.5) = 0.5 / 0.5 = 1

- 50 / (- 0.5) = 50 / 0.5 = 50 / (5/10) = 50 / (1/2) = 50 * 2/1 = 100

The correct results would be: (- 0.5) / (- 0.5) = 1 and - 50 / (- 0.5) = 100.

6 0

3 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago