Considering the situation described, we have that:
a) The critical value is of z = -1.645.
b) Since the test statistic is less than the critical value, we should reject the null hypothesis H0.
<h3>What is the critical value?</h3>
We have a left-tailed test, as we are testing if the proportion is less than a value. Hence the critical value is z with a p-value equals to the significance level, hence z with a p-value of 0.05, hence z = -1.645.
<h3>What is the decision?</h3>
Considering the test statistic, for a left-tailed test, we have that:
- Less than the critical value: Reject H0.
- Equal or greater: Do not reject.
In this problem, z = -2.39 is less than -1.645, hence we should reject the null hypothesis H0.
More can be learned about the test of an hypothesis at brainly.com/question/13873630
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From the given description it seems that the small shaded circle lies within the larger circle as shown in image below:
The probability that a point choosen at random lies within the shaded area = Area of shaded region / Total area of the bigger cricle
So,
Probability = 78.5/314 = 0.25
Thus there is 0.25 or 25% probability that the point chosen at random will lie inside the shaded region.
Answer: 5/6 > 29/36
<u>Find Common Denominator</u>
6: 6,12,18,24,30,36
36: 36,72,106
CD=36
<u>Multiply both sides by 6</u>
5/6×6/6=30/36
<u>Compare</u>
30/36 > 29/36
<u>Therefore</u>
5/6 > 29/36
C- charge
H- hours
D- diagnostic fee
C= #H(90)+ D
C= 4.6(90)+50
=414+50
=$464
C-$800
H-?
D-50
C= #H(90)+50
800=H(90)+50
H(90)=800-50
H(90)=750
H(90)/90=750/90
H=750/90
H= 8.33333333
For the square to fit inside the circle without touching it, the diagonal of the square needs to be less than the diameter of the circle.
Using the Pythagorean theorem we can calculate the diagonal of the square:
X = SQRT(5^2 + 5^2)
X = SQRT(25 + 25)
X = SQRT(50)
X = 7.07
The diagonal of the square is 7.07 cm, which is less than the diameter of the circle, 9cm, so it will fit .
