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SpyIntel [72]
3 years ago
12

What is the asymptote of the exponential function y = abx + c?

Mathematics
1 answer:
vredina [299]3 years ago
7 0
The correct answer to this question is Choice D: y = c

This is a horizontal asymptote at y = c. The c is the constant value that is added on to the function. The first part of the equation "y=ab^x" is always going to be a positive number bigger than zero. Therefore, the graph will always be just a little bit bigger than c, it can't equal c.
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Answer:

t= -2.5

Step-by-step explanation:

2t−5=−10

add 5 to both sides

2t= -5

divide by 2

t= -2.5

5 0
3 years ago
6√18 + 3√50 simply ?
-BARSIC- [3]
33square2  i think that is what it is
4 0
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Using Logarithmic Properties to Solve an Equation<br> plsssss help mee!!!!
saw5 [17]

Answer:

1). x=5

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8 0
3 years ago
300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a do
katrin2010 [14]

This Question is not complete

Complete Question:

300 students in a high school freshman class are surveyed about what kinds of pets they have. Of the 300 students, 200 have a dog, 180 have a cat, and 150 have a cat and a dog. Using this information, answer each of the following questions, Let D be the event that a randomly selected student has a dog and C be the event that a randomly selected student has a cat.

a . What is P(D), the probability that a student in the class has a dog?

b. What is P(C), the probability that a student in the class has a cat?

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

Answer:

a. 2/3

b) 3/5

c) 1/2

d) 19/ 15 = 1 4/15

Step-by-step explanation:

The formula for probability =

Number of possible outcomes ÷ Number of events.

Total number of Students = 300

Number of Students that have a dog = 200

Number of Students that have a cat = 180

Number of Students that have a dog and cat = 150

a. What is P(D), the probability that a student in the class has a dog?

In the question, the given data is interpreted as :

Number of possible outcomes = 200

Number of events = 300

P(D) = 200/300

= 2/3

Therefore, the probability that a student has a dog = 2/3

b. What is P(C), the probability that a student in the class has a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 180

Number of events = 300

P(D) = 180/300

= 3/5

Therefore, the probability that a student has a cat = 3/5

c. What is P(D and C), the probability that a student in the class has a dog and a cat?

In the question, the given data is interpreted as :

Number of possible outcomes = 150

Number of events = 300

P(D) = 150/300

= 1/2

Therefore, the probability that a student has a dog and cat = 1/2

d. What is P(D or C), the probability that a student in the class has a dog or a cat?

The is calculated as

P(D) + P(C)

In the above question,

P(D) is calculated as 2/3

P(C) is calculated as 3/5

Therfore, P(D or C), the probability that a student in the class has a dog or a cat is calculated as:

= 2/3 +3/5

= 19/15 = 1 4/15

7 0
3 years ago
Can anyone help me please? Also explain if you can. Thank you :)
djverab [1.8K]
The answer is 6/9 or 2/3 because 2X2X2=8 and 9X9X9=729......it equals 8/729 






3 0
3 years ago
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