A parabola is a quadratic function, and a quadratic can be expressed in vertex form, which is:
y=a(x-h)^2+k, where (h,k) is the vertex (absolute maximum or minimum point of the quadratic)
In this case we are given that (h,k) is (-5,80) so we have so far:
y=a(x--5)^2+80
y=a(x+5)^2+80, we are also told that it passes through the point (0,-45) so:
-45=a(0+5)^2+80
-45=25a+80 subtract 80 from both sides
-125=25a divide both sides by 25
-5=a, so now we know the complete vertex form is:
y=-5(x+5)^2+80
The x-intercepts occur when y=0 so:
0=-5(x+5)^2+80 add 5(x+5)^2 to both sides
5(x+5)^2=80 divide both sides by 5
(x+5)^2=16 take the square root of both sides
x+5=±√16 which is
x+5=±4 subtract 5 from both sides
x=-5±4 so the x-intercepts are:
x=-1 and -9
Answer:
First notice that they’re asking for the absolute value of the equation.
The absolute value is how far that number is from 0.
Basically it’s the number without a negative sign.
ok so 6-27 = -21
The product for 6-27 (21) is 21 spaces away from 0.
|6-27| = 21
21 is the answer to your question.
Hope this helped and pls mark me brainliest if it did :)
Answer:
I think it is 8, i did not learn this in school
Step-by-step explanation:
2(3x^2+5)
6x^2+10
