Answer:
x = 2 cm
y = 2 cm
A(max) = 4 cm²
Step-by-step explanation: See Annex
The right isosceles triangle has two 45° angles and the right angle.
tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x
A(r) = x* y
Area of the rectangle as a function of x
A(x) = x * ( 4 - x ) A(x) = 4*x - x²
Tacking derivatives on both sides of the equation:
A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0
2*x = 4
x = 2 cm
And y = 4 - 2 = 2 cm
The rectangle of maximum area result to be a square of side 2 cm
A(max) = 2*2 = 4 cm²
To find out if A(x) has a maximum in the point x = 2
We get the second derivative
A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2
Answer:
Step-by-step explanation:



Set each factors equal to zero.


The x-int is

Answer:
Step-by-step explanation:
Answer:
(x-1)²+(y-3.5)² = 265/4
Step-by-step explanation:
first find the midpoint (center of the circle)
(9+-7)/2, (2+5)/2
(1, 3.5) = center
then distance formula to find diameter
√(9- -7)²+(2-5)²=√256+9 = √265
The radius is half the diameter = (√265)/2
Formula for circle is (x-h)²+(y-k)²=r², where (h, k) is the center
Now you can plug everything in.
(x-1)²+(y-3.5)² = 265/4
Answer:
1. Area of a square = (x^2)^2 = x^4
(each side is x^2, area of a square = side^2
so (x^2)(x^2) = x^4 )
2. when x = 5
area = 5^4 = 625
3. when x = 10
area = 10^4 = 10000
Step-by-step explanation:
Hope its right!
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