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3 years ago

Write the function in function notation: y=7b+8

Mathematics

1 answer:

kow [346]3 years ago

3 0

You would just write f(x) (f of x) in for y: f(x) = 7x + 8.
Hope it helps.

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3 times the first of three consecutive odd integers is 3 more than twice the third? what is the third integer

fenix001 [56]

Answer:

Step-by-step explanation:

The difference between consecutive integers is 1.

The difference between consecutive odd integers is 2.

Let the smallest odd integer be x.

Then the next greater one is x + 2. The greatest one is x + 4.

"3 times the first" is 3x

"twice the third" is 2(x + 4)

"3 times the first of three consecutive odd integers is 3 more than twice the third"

3x = 2(x + 4) + 3

3x = 2x + 8 + 3

x = 11

The smallest integer is 11.

x + 4 = 11 + 4 = 15

The greatest one is 15.

4 0

3 years ago

Write the expression in expanded form that is equivalent to 3(7d +4e)

pickupchik [31]

Answer:

21+4

Step-by-step explanation:

3 times 7=21

3 times4=12

21d+4e

4 0

2 years ago

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Please don’t skip!!! I need help!!

horsena [70]

P = [60] cm

Explanation:

6.5 cm + 6.5 cm + 7.5 cm + 7.5 cm + 7.5 cm + 7.5 cm + 8.5 cm + 8.5 cm

7 0

3 years ago

What is the area of a cylindrical ring where the diameter of the cross section is 6.3 in and the center line has a length of 48

Nesterboy [21]

Answer:

The area of cylinder 949.536 in²

Step-by-step explanation:

Points to remember

Curved surface area of cylinder = 2πrh

Where r - radius of cylinder

h - Height of cylinder

<u>To find the area of cylinder</u>

Here r = diameter/2 = 6.3/2 = 3.15 in

h = 48 in

Area = 2πrh

= 2 * 3.14 * 3.15 * 48

= 949.536 in²

Therefore area of cylinder 949.536 in²

4 0

3 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

3 years ago

Read 2 more answers