Answer:
The equation of the relation ⇒ 
y = 18
Step-by-step explanation:
∵ y ∝ x/z
∴ y = kx/z
∵ y = 18 , x = 15 and z = 5
∴ 18 = 15k/5 ⇒ 18 = 3k
∴ k = 18/3 = 6
∴ y = 6x/z
∵ x = 21 and z = 7
∴ y = (6 × 21)/7 = 18
y = 6x - 4
Substitute the given x values to solve for y.
x = 1:
y = 6(1) - 4
y = 6 - 4
y = 2
1 = 2
x = 3:
y = 6(3) - 4
y = 18 - 4
y = 14
3 = 14
x = 10:
y = 6(10) - 4
y = 60 - 4
y = 56
10 = 56
x y
1 2
3 14
10 56
Yes, all of the rhombuses have 2 pairs of parallel side.
Answer:
1 2/21
Step-by-step explanation:
We start out with:
3/7 + 2/3
In order to add them together, they must have an equal denominator. An easy way to find an equal denominator is the cross method. We divide 7 by 3 and 3 by 7, giving us a denominator of 21:
3/21 + 2/21
But what about the numerators? You do the same thing as before (multiplying by the other's denominator). Now we have:
9/21 + 14/21
We add both together (the denominator stays the same) and we get 23. 23/21 is correct but not in simplest form. We remove 21 from the numerator (because it is a whole) and finally get:
1 2/21!
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In a quadratic equation with the general formula of:
ax^2 + bx + c = 0
The discriminant is equal to b^2 - 4(a)(c). If the answer is a perfect square, then there are two real numbers. If not, then there are no real number root.
The discriminant for this equation is
(-6)^2 - 4(3)(1) = 24
Since 24 is not a perfect square, there are no real number roots.
