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1 year ago

Is this a valid argument?

Mathematics

1 answer:

Andreas93 [3]1 year ago

6 0

Yes, this is a valid argument. This argument uses the Law of Detachment.

<h3>What is the Law of Detachment in logic?</h3>

The Law of Detachment states that if the hypothesis of a true conditional statement is true, then the conclusion must be true as well. The Law of Detachment is the most often employed deductive reasoning theory.

Given:

Points X and Y both lie on plane R.

Conclusion: Points X and Y are coplanar.

The argument is true because,

The term "coplanar" refers to "being on the same plane." Coplanar points are points that are on the same plane. A group of points in space is said to be coplanar if there is a geometric plane that contains all of them.

Hence, the Conclusion is Points X and Y are coplanar.

To learn more about arguments visit:

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Finding the missing angles 35° and 145°

padilas [110]

Answer:

Step-by-step explanation:

There are two ways to find the value of X

$x + 35 = 180$ ( sum of co-interior angles)

Move constant to R.H.S and change its sign

$x = 180 - 35$

Calculate the difference

$x = 145$ °

You can use another way too.

$x = 145$ ° ( being vertically opposite angles)

Vertically opposite angles are always equal.

Hope this helps...

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2 years ago

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Step-by-step explanation:

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2 years ago

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This is my last question please help asap!!

Ivanshal [37]

The average rate of change of function $g(x)=5(2)^{x}$ from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.

The correct option is (A).

What is the average rate of change of a function?

The average rate at which one quantity changes in relation to another's change is referred to as the average rate of change function.

Using function notation, we can define the Average Rate of Change of a function f from a to b as:

$rate(m) = \frac{f(b)-f(a)}{b-a}$

The given function is $g(x) = 5(2)^{x}$ ,

Now calculating the average rate of change of function from x = 1 to x = 2.

$m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(2)-g(1)}{2-1}\\\\m=\frac{5(2)^{2}-5(2)^1}{2-1}\\ m=\frac{10}{1} \\m=10$

Now, calculate the average rate of change of function from x = 3 to x = 4.

$m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(4)-g(3)}{4-3}\\\\m=\frac{5(2)^{4}-5(2)^3}{4-3}\\ m=\frac{40}{1} \\m=40$

The jump from m = 10 to m = 40 is "times 4".

So option (A) is correct.

Hence, The average rate of change of function $g(x)=5(2)^{x}$ from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.

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1 year ago

PLEASE HELP PLEASEEE!!!!

shtirl [24]

In first diameter=8,In second diameter=2/3,

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2 years ago

Three and two forths - one and two thirds = <br> 3 2/4 - 1 2/3 =

soldier1979 [14.2K]

Answer:

1.83333333333

Step-by-step explanation:

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ok thanks :) :) :) :)

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2 years ago