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cestrela7 [59]
1 year ago
6

Is this a valid argument?

Mathematics
1 answer:
Andreas93 [3]1 year ago
6 0

Yes, this is a valid argument. This argument uses the Law of Detachment.

<h3>What is the Law of Detachment in logic?</h3>

The Law of Detachment states that if the hypothesis of a true conditional statement is true, then the conclusion must be true as well. The Law of Detachment is the most often employed deductive reasoning theory.

Given:

Points X and Y both lie on plane R.

Conclusion: Points X and Y are coplanar.

The argument is true because,

The term "coplanar" refers to "being on the same plane." Coplanar points are points that are on the same plane. A group of points in space is said to be coplanar if there is a geometric plane that contains all of them.

Hence, the Conclusion is Points X and Y are coplanar.

To learn more about arguments visit:

brainly.com/question/5756468

#SPJ13

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,nm

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Warm fronts and stationary fronts bring? (A) severely bad weather (B) clear skies (C) light precipitation (D) mid-latitude cyclo
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Select the values that make b≥-3 true
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-3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10+

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and anything above 10 would be true

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Best answer gets the brainliest!<br> Find $a/b$ when $2\log{(a -2b)} = \log{a} + \log{b}$.
andrey2020 [161]

By some properties of logarithms, rewrite the equation as

2\log(a-2b) = \log(a) + \log(b) \\\\ \log(a-2b)^2 = \log(ab)

so that

(<em>a</em> - 2<em>b</em>)² = <em>ab</em>

Expand the left side:

<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>

Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :

<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0

<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get

<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0

Factorize and solve for <em>a</em>/<em>b</em> :

(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0

==>   <em>a</em>/<em>b</em> = 4   or   <em>a</em>/<em>b</em> = 1

However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with

<em>a</em>/<em>b</em> = 4

5 0
2 years ago
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