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Licemer1 [7]
3 years ago
7

The perpendicular bisector of the line segment connecting the points (-3,8) and (-5,4) has an equation of the form y = mx + b. F

ind m+b. BTW, the answer is not 16...
Mathematics
2 answers:
omeli [17]3 years ago
8 0

Answer:

Step-by-step explanation:

find the slope

\frac{4-8}{-5-(-3)} =\frac{-4}{-2} \\\\slope=2\\y=mx+b\\y=2x+b\\

take a coordinate to fill in

(-5,4)\\y=-5\\x=4\\-5=2(4)+b\\-5=8+b-8   -8\\-13=b\\

this means that the equation is y=2x-13

and if you add m and b

you get :-11

<u><em>I HOPE THIS HELPS</em></u>

ICE Princess25 [194]3 years ago
6 0

Answer:

7/2

Step-by-step explanation:

Let $A = (-3,8)$ and $B = (-5,4)$. The midpoint of $\overline{AB}$ is $\left( \frac{(-3) + (-5)}{2}, \frac{8 + 4}{2} \right) = (-4,6)$.

The slope of $\overline{AB}$ is $\frac{8 - 4}{(-3) - (-5)} = 2$, so the slope of the perpendicular bisector of $\overline{AB}$ is $-\frac{1}{2}$. Therefore, the equation of the perpendicular bisector is given by

\[y - 6 = -\frac{1}{2} (x + 4).\]Isolating $y,$ we find

\[y = -\frac{1}{2} x + 4.\]

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