Im assuming you mean 2x^2-3x-9=0 ?
If so, you have to factorise the equation
(2x-3) (x+3) = 0
2x - 3 = 0
2x = 3
x = 1.5
x + 3 = 0
x = -3
x is either 1.5 or -3
Answer:
Well u would multiply 20 x 15 to find out the highest if the range which is 300 . So that knocks it down to B or D. But since they're $15 each, It would be based of the multiples of 15 making your answer B .
The range is all the y values.....or the f(x) values .
So the practical range would be the multiples of 15 between 0 and 300,Inclusive .
<h2>Hope this helps you!! </h2>
