Answer:
Explanation:
Job 11-101=$3,880
Job 11-102= $2,630
Job 11-103= $2,080
Job 11-104= $3,190
Job 11-105= $2,080
Total 13,860
Direct labor rate = $18
Predetermined overhead rate = $22
Direct labor hour = 13,860/18 = 770 hours
Applied factory overhead rate = 770 *22 = $16,940
Factory labor cost
Dr Cr
Work in progress 13,860
Factory Overhead 18,000
Wages payable 31,860
Factory Overhead
Work in progress 16,940
Factory overhead 16,940
You can fund a four-year college degree by either of the following:
1. Loans
Loans can be acquired through federal aid or private means. They must be paid back with interest when the student has graduated. They are guaranteed by the federal government.
2. Scholarships
Scholarships depends on criterias from who will sponsor it. These criterias may include financial need, merits, field of study, etc. There are those who can help students look for a scholarship that fit them like counselors, the government or its agency, community organizations, etc.
3. Work-study programs
They operate with the financial aid office of the school. However, they require the student's determination and financial needs.
Answer: Maximize joint welfare in respective or the right owner.
Explanation: A coase solution to a problem of externality insures that a socially efficient outcome is to maximize the joint welfare, irrespective of the right of ownership.
The Coase theorem states that when transaction cost are low, two parties will be able to bargain and reach an efficient outcome in the presence of an externality.
The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5
<u>Given data :</u>
Mean value of gasoline per hour = 875 gallons
Standard deviation = 55 gallons
<h3>Determine the probability of demand being greater than 1800 gallons over 2 hours </h3>
Demand for gas in 1 hour = X₁
Demand for gas in 2 hours = X₁ + X₂
Therefore ; ( X₁ + X₂) ~ N ( u₁+u₂, sd₁² + sd₂² )
In order to calculate probabilities for normals apply the equation below
Z = ( X- u ) / sd
where : u = 1800, sd = √ ( 55² + 55² ) = 77.78
using the z-table
P( Y > 1800) = P( Z > ( 1800 - 1800 ) / 77.78)
= P( Z>0 ) = 0.5
Hence we can conclude that The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5.
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