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mina [271]
4 years ago
12

A carpenter wants to put four shelves on a 8-foot wall(=b) so that the five spaces created decrease by 7 inches(=a) as we move u

p the wall. If the thickness of each shelf is
3/4 inch, how far will the bottom shelf be from the floor?
Mathematics
1 answer:
nadezda [96]4 years ago
3 0

Height of wall = 8 feet

1 feet = 12 inches

⇒ Height of wall = 8 × 12 inches

⇒ Height of wall = 96 inches

We know that the 4 shelves are to be placed such that that the 5 spaces created decrease by 7 inches as we move up the wall

Let height of 1st space = h inches

⇒ Height of 2nd space = h - 7 inches

⇒ Height of 3rd space = h - 14 inches

⇒ Height of 4th space = h - 21 inches

⇒ Height of 5th space = h - 28 inches

Thickness of each shelf = 3/4 inch

⇒ Thickness of 4 shelves = \frac{3}{4} × 4 inches = 3 inches

So, Height of Wall = Height of 1st space + Height of 2nd space + Height of 3rd space + Height of 4th space + Height of 5th space + Thickness of 4 shelves

⇒ 96 = h + h - 7 + h - 14 + h -21 + h - 28 + 3

⇒ 95 = 5h - 70 + 3

⇒ 95 = 5h - 67

⇒ 5h = 162

⇒ h = 32.4 inches

So the first shelf is placed 32.4 inches from the floor

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Identify the zeros of f(x) = (x + 9)(x − 4)(6x + 1).
slavikrds [6]
<h2>The required 'option a)  - 9 , \dfrac{-1}{6}, 4' is correct.</h2>

Step-by-step explanation:

We have,

f(x) = (x + 9)(x − 4)(6x + 1)

To find, all zeroes of the given equation = ?

∴ f(x) = (x + 9)(x − 4)(6x + 1)

⇒ (x + 9)(x − 4)(6x + 1) = 0

⇒ x + 9 = 0 or, x − 4 = 0 or, 6x + 1 = 0

⇒ x + 9 = 0 ⇒  x = - 9

⇒ x − 4 = 0 ⇒ x = 4

⇒ 6x + 1 = 0

⇒ 6x = - 1

⇒ x = \dfrac{-1}{6}

∴ x = - 9 , \dfrac{-1}{6}, 4

Thus, the required 'option a)  - 9 , \dfrac{-1}{6}, 4' is correct.

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Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye
svetlana [45]

Answer:

The required recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

Year \: 1 = 500

Each year thereafter the number of leaves was 40% more than the year before so that means

Year \: 2 = 500(1+0.40) = 500\times 1.4\\

For the third year the number of leaves increase 40% than the year before so that means

Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\

Similarly for fourth year,

Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

f(n)= 500\times(1.4)^{n-1}\\

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330

So there will be 10330 leaves in the 10th year.

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3 years ago
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