A system of equations is given below.

What is the quotient?7-4ーks130-5○ 75〇fl517 777-7C园燜

Artist 52 [7]

$Use\ \dfrac{a^n}{a^m}=a^{n-m}\\\\\dfrac{7^{-4}}{7^{-9}}=7^{-4-(-9)}=7^{-4+9}=7^5$

8 0

3 years ago

The area of an artist's square canvas can hold 113 square inches of paint. What is the approximate length of one side of the can

xeze [42]

The area of any rectangle is:

A=xy, and a square is just a special rectangle where the two dimensions are equal. x=y=s, where s is the side length so the area of a square is:

A=s^2 we want to solve for s so

s^2=A

s=√A, and we are told that the area is 113 in^2

s=√113 in

s≈10.63 in (to nearest hundredth of an inch)

5 0

2 years ago

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,

valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

μ = 144 mm

σ = 7 mm

n = 50.

Since n = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

$\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)$

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

$P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})$

$=P(Z>2.63)\\=1-P(Z$

*Use a z-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0

2 years ago

PLEASE HELP 7TH GRADE 100 PTS!!!

MariettaO [177]

f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.

f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.

So for Section A:

f(x) = 5x, (0,1)

[f(1) - f(0)]/(1-0)

= [5(1) - 5(0)]/1

=(5)/1

=5

Do the same for section B and you'll get 5 as well.

I hope this helps you because I have no clue if my answer is right

6 0

3 years ago

Daniel had 4 times as many stickers as Adrian. He then put his stickers equally into 8 albums. If Adrain had 76 stickers, how ma

il63 [147K]

Daniel put 38 stickers in each album

8 0

3 years ago

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