All categories

2 years ago

Verify the identity. Please show your work.

Mathematics

1 answer:

m_a_m_a [10]2 years ago

5 0

Step-by-step explanation:

To prove :

( 1 - sin x ) ( 1 + sin x ) = sec² x

LHS : -

( 1 - sin x ) ( 1 + sin x )

Formula / Identity : -

( a - b ) ( a + b ) = a² - b²

Here,

a = 1

b = sin x

( 1 - sin x ) ( 1 + sin x )

= 1 - sin² x

Identify : -

sin² θ + cos² θ = 1

cos² θ = 1 - sin² θ

Similarly,

1 - sin² x

= cos² x

= RHS

Hence verified.

You might be interested in

Does anyone know the answer

murzikaleks [220]

Answer:

20,160

Step-by-step explanation:

6 0

2 years ago

Carly is a catcher on the school softball team. By the end of the season, she had played 45% of the 49 games the team played. In

Eduardwww [97]

Carly did not play 22 games

6 0

2 years ago

Rewrite the following expression in logarithmic form and use that to solve for the variable. Show all work done in this process.

Llana [10]

Answer:

$ln(e^x)=ln(3)$

$x=1.099$

Step-by-step explanation:

You have the following exponential expression:

$2e^x=6$

You need to divide both sides of the equation by 2:

$\frac{2e^x}{2}=\frac{6}{2}\\\\e^x=3$

Now apply the function Natural logarithm to both sides of the function:

$ln(e^x)=ln(3)$

Note that now the exponential function is transformed into a logarithmic function.

By definition:

$ln(e^x)=x$ Because the base of the Natural logarithm is the Euler's number "e".

Then you can solve for "x":

$x=ln(3)\\x=1.099$ )

7 0

2 years ago

Divide the given polynomial by the given monomial.

sasho [114]

Answer:

Here is the answer. Solved

5 0

2 years ago

A and b are positive integers. Find −2a+3b if a^3*b^2=72.

MAXImum [283]

${a}^{3} {b}^{2} = a \times a \times a \times b \times b \\ 72 = 2 \times 2 \times 2 \times 3 \times 3 = {2}^{3} {3}^{2} \\ {a}^{3} {b}^{2} = 72 \\ \Rightarrow a = 2,b = 3 \\ \Rightarrow - 2a + 3b = - 2 \times 2 + 3 \times 3 = - 4 + 9 = 5$

3 0

2 years ago