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3 years ago

Plzzzzz help me and my dad are confused we can’t get them right

Mathematics

1 answer:

o-na [289]3 years ago

3 0

If you are using a calculator, follow PEMDAS which states that you do division first then add. So do 3 divided by 1 1/3 and then add the 1/2

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(1.2)Consider the diagram below. Identify a point.

Fynjy0 [20]

Option B is correct. Point F is the only point according to the option given

A point is defined as an exact location with no size, length, or even width.

From the diagram shown, we have points, plane, and line segments.

The only plane that we have is plane R making option C incorrect.

A line is defined as a straight figure connected by two points. From the diagram, the line segments that we have are AN, BN, and AB falsifying options A and D.

The points are C, D, E, and F. Hence the correct option is B. Point F is the only point according to the option given

Learn more here: brainly.com/question/13099718

6 0

3 years ago

The equation below describes a parabola. If a is negative, which way does the parabola open?

const2013 [10]

Given equation : y=ax^2
Taking a to the other side we have, x^2=(1/a)*y
This equation describes a parabola that opens up.
When a is negative, the focus is on the negative y-axis, therefore, the parabola opens down.
The answer is a. down.

6 0

3 years ago

Read 2 more answers

A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one

TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are $\binom44\binom{48}1=48$ possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by $\binom{13}1=13$ . So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

$\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024$

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing $\binom41\binom{48}4=778,320$ possible hands. Exactly 2 aces are drawn in $\binom42\binom{48}3=103,776$ hands. And so on. This gives a total of

$\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656$

possible hands containing at least 1 ace, and hence B occurs with probability

$\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412$

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. $P(A\cap B)=P(A)P(B)$ . This happens if

the hand has 4 aces and 1 non-ace, or
the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So $A\cap B$ consists of 96 possible hands, which occurs with probability

$\dfrac{96}{\binom{52}5}\approx0.0000369$

and so the events A and B are NOT independent.

4 0

3 years ago

What is the value of z? 117°

mario62 [17]

Hi I would love to help but the picture is black

6 0

2 years ago

Melanie swarm for 142 minutes during her first week of vacation. In her two weeks of vacation she swam for a total of 347 minute

Soloha48 [4]

Answer: Melanie swam 63 minutes more in second week.

Step-by-step explanation:

Given , Time taken by Melanie in first week to swim = 142 minutes

Combined time taken by her in first two weeks in swimming = 347 minutes

Now , time taken by her in second week = (Combined time of first two week) - (Time taken in first week)

= 347-142 minutes

= 205 minutes

Clearly , 205 > 142 i.e. She swam more in second week than first week./

Difference i= 205-142 = 63

Therefore, Melanie swam 63 minutes more in second week.

3 0

3 years ago