The expression for the greatest common factor of 20 and 30 using the distributive property is 10(2 + 3)
Pounds of ice = 20
Number of cups = 30
The relation for the distributive property :
a × (b + c)
Expand ;
a × (b + c) = (a × b) + (a × c) = ab + ac
Finding the greatest common factor of 20 and 30 ;
(2 × 10) + (3 × 10)
According to the distributive property
(2 × 10) + (3 × 10) = 10(2 + 3)
Therefore, the expression for the greatest common factor is 10(2 + 3)
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Answer:
10 cm
Step-by-step explanation:
The area (A) of a rhombus is calculated as
A =
× d₁ × d₂ ( d₁ and d₂ are the diagonals )
Here A = 60, d₁ = 12, thus
60 = 0.5 × 12 × d₂ = 6 d₂ ( divide both sides by 6 )
d₂ = 10
The other diagonal is 10 cm
B is the answer to your question
You would expand becausee it isn't equal to anything
(x+3)^3=(x+3)(x+3)(x+3)
we can use binomial theorem or pascal's triangle
anyway, pascal's triangle is more practicl for this one
so
for the 3rd power

a=x
b=3

=