B a perfect cube because 5 cubed is 125
Answer:
98
Step-by-step explanation:
So we have the two functions:
And we want to find the value of r(g(4)).
To do so, first find the value of g(4):
Multiply:
Subtract:
Now, substitute this into r(g(4)):
And substitute this value into r(x):
Square:
Subtract:
Therefore:
Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
32
Step-by-step explanation:
Answer:
5391.76
Step-by-step explanation:
We have a rectangle and 2 semicircles
First find the area of the rectangle
A = l*w
A = 44*88= 3872
Then we know that 2 semicircles = 1 circle
The area of a circle is
A = pi r^2
The diameter is 44 so the radius is 22
A = pi * 22^2
A = pi484
A =1519.76
Add the areas together
1519.76+3872
5391.76
