Please help don’t know how to start this

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

6 0

A. Area is length times width so it would be

3*5=15

15ft^2

B. 3*10=30

30+15= 45

45ft^2 when pushed together

C. 54-45=9

Table three has an area of 9ft^2

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Which of the following give an equation of a line that passes through the point (6/5,-19,5) and is parallel to the line that pas

Ilya [14]

Parallel lines, have the same slope, so the slope of the line through 0,0 and -2,-12, is the same as for the line running through (6/5,-19.5) as well, so what is it anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 0}}\quad ,&{{ 0}})\quad 
% (c,d)
&({{ -2}}\quad ,&{{ -12}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-12-0}{-2-0}\implies \cfrac{-12}{-2}\implies 6$

so, we're looking for the equation of a line whose slope is 6, and goes through (6/5,-19/5)

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ \frac{6}{5}}}\quad ,&{{ -\frac{19}{5}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\left( -\frac{19}{5} \right)=6\left(x-\frac{6}{5} \right)
\\\\\\
y+\cfrac{19}{5}=6x-\cfrac{36}{5}\implies y=6x-\cfrac{36}{5}-\cfrac{19}{5}\implies y=6x-\cfrac{55}{5}
\\\\\\
y=6x-11$

6 0

2 years ago

Please help!

Mrrafil [7]

Answer:

$\sf C. \quad \dfrac{1}{9}$