Which number is located at the point Q on the number line?
1 answer:
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Answer:
And solving we got:
We can find the sings of the second derivate on the following intervals:
Concave up
inflection point
Concave down
inflection point
Concave up
Step-by-step explanation:
For this case we have the following function:
We can find the first derivate and we got:
In order to find the concavity we can find the second derivate and we got:
We can set up this derivate equal to 0 and we got:
And solving we got:
We can find the sings of the second derivate on the following intervals:
Concave up
inflection point
Concave down
inflection point
Concave up
Ok so first, you put the sides into a ratio. The question says that triangle GKNM is congruent to triangle VRPT. From this, we know that side GK is congruent to VR. So, we write that as a ratio. Also, we know that KN is congruent to RP. We also write that as a ratio. Then, using equations, we solve for x. But, we aren't done yet; the expression for side KN is 3x-2 and, we already know that x is equal to 4.4
So, we do 3*4.4-2 which is 11.2. Therefore, side KN is equal to 11./2Then, the expression for side RP is x+4. We already know that x is equal to 4.4. So, we do 4.4+4 which is 8.4. Therefore, side RP is equal to 8.4.
Oh, and the scale factor is 4:3 or 1.33 because you do 8.4/6.3 ( you can also do 11.2/8.4)
hope this helps ;)
So, we do 3*4.4-2 which is 11.2. Therefore, side KN is equal to 11./2Then, the expression for side RP is x+4. We already know that x is equal to 4.4. So, we do 4.4+4 which is 8.4. Therefore, side RP is equal to 8.4.
Oh, and the scale factor is 4:3 or 1.33 because you do 8.4/6.3 ( you can also do 11.2/8.4)
hope this helps ;)
The image below shows y = 5/3x - 9 being graphed.
Hope this helps! :)
