in the given diagram, which of the following can you use to prove that triangle ABC is an isosceles triangle?

Mathematics

1 answer:

ryzh [129]3 years ago

5 0

If the triangle has two congruent sides.

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Factor completely. -2k - k3^ - 3k^2

wlad13 [49]

Answer:

$-k(k+1)(k+2)$

Step-by-step explanation:

Begin to factor by using GCF by finding the greatest common factor. Here it is k.

$-2k-k^3-3k^2 = -k(2+k^2+3k)$

We will rearrange and factor the trinomial.

$-k(2+k^2+3k)\\-k(k^2+3k+2)\\-k(k+1)(k+2)$

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3 years ago

Which expression is equivalent to 173/22

Advocard [28]

Answer:

7.863

Step-by-step explanation:

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3 years ago

Read 2 more answers

Solve each system using elimination. tell whether the system has one solution, infinitely many solutions, or no solution.

Tomtit [17]

1.
$x-2y=-1 \\
2x+y=4 \ \ \ |\times 2 \\ \\
x-2y=-1 \\
\underline{4x+2y=8 \ } \\
x+4x=8-1 \\
5x=7 \\
x=\frac{7}{5} \\
x=1 \frac{2}{5} \\ \\
x-2y=-1 \\
\frac{7}{5}-2y=-1 \\
-2y=-1-\frac{7}{5} \\
-2y=-\frac{5}{5}-\frac{7}{5} \\
-2y=-\frac{12}{5} \\
y=\frac{6}{5} \\
y=1 \frac{1}{5} \\ \\
\boxed{(x,y)=(1\frac{2}{5}, 1 \frac{1}{5}) \Leftarrow \hbox{one solution}}$

2.
$x+3y=4 \ \ \ |\times 2 \\
2x-6y=8 \\ \\
2x+6y=8 \\
\underline{2x-6y=8} \\
2x+2x=8+8 \\
4x=16 \\
x=4 \\ \\
x+3y=4 \\
4+3y=4 \\
3y=4-4 \\
3y=0 \\
y=0 \\ \\
\boxed{(x,y)=(4,0) \Leftarrow \hbox{one solution}}$

3.
$y=-\frac{1}{2}x-3 \ \ \ |\times (-2) \\
x+2y=-6 \\ \\
-2y=x+6 \\
\underline{x+2y=-6 \ } \\
x=x+6-6 \\
x-x=6-6 \\
0=0 \\ \\
\boxed{\hbox{infinitely many solutions}}$

4.
$6x-3y=-18 \\
-2x+4y=18 \ \ \ |\times 3 \\ \\
6x-3y=-18 \\
\underline{-6x+12y=54} \\
-3y+12y=54-18 \\
9y=36 \\
y=4 \\ \\
6x-3y=-18 \\
6x-3 \times 4=-18 \\
6x-12=-18 \\
6x=-18+12 \\
6x=-6 \\
x=-1 \\ \\
\boxed{(x,y)=(-1,4) \Leftarrow \hbox{one solution}}$

3 0

3 years ago

14=2y/5 and explain how you got it??

son4ous [18]

2y/5 is the same thing as 2/5 times y so

14=2/5(y) then you divide both sides by y and you get

14/y=2/5 then from there multiply both sides by 1/14 to get

y=0.03

5 0

3 years ago

What is the exact value of cos(c + d), given sinc =24/25 for c in Quadrant II and cos d =-3/4 for d in Quadrant III?

Y_Kistochka [10]