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scoundrel [369]

3 years ago

6

Find the difference (4ab-9a-8)-(7ab-1)

1 answer:

OLga [1]3 years ago

7 0

(4ab - 9a - 8) - (7ab - 1)
distribute (multiply) the negative through the parenthesis
<span>(4ab - 9a - 8) - 7ab + 1
No need for other parenthesis because nothing in front or to combine inside. </span>
<span>4ab - 9a - 8 - 7ab + 1 </span>
Combine like terms
- 3ab - 9a - 7

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Find height of triangle given hypotenuse and angle

harkovskaia [24]

Given h is the height, H is the hypotenuse and A is the base angle,
then Sin(A) = h/H
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3 years ago

It is known that the population variance equals 484. With a .95 probability, the sample size that needs to be taken to estimate

Hitman42 [59]

Answer:

The minimum sample size is n = 75 so that the desired margin of error is 5 or less.

Step-by-step explanation:

We are given the following in the question:

Population variance = 484

Standard deviation =

$\sigma^2 = 484\\\sigma =\sqrt{484} = 22$

Confidence level = 0.95

Significance level = 0.05

Margin of error = 5

Formula:

Margin of error =

$E = z\times \dfrac{\sigma}{\sqrt{n}}\\\\n = (\dfrac{z\times \sigma}{E})^2$

$z_{critical}\text{ at}~\alpha_{0.05} = 1.96$

Putting values, we get

$E\leq 5\\\\1.96\times \dfrac{22}{\sqrt{n}} \leq 5\\\\\sqrt{n} \geq 1.96\times \dfrac{22}{5}\\\\n \geq (1.96\times \dfrac{22}{5})^2\\\\n \geq 74.373$

Thus, the minimum sample size is n = 75 so that the desired margin of error is 5 or less.

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2 years ago

After being rearranged and simplified, which of the following equations could

masha68 [24]

Answer:

C and D

Step-by-step explanation:

The quadratic formula is

x= (-b±√b²-4ac)/2a

The formula uses the numerical coefficients in the quadratic equation.

The general quadratic equation is ax²+bx+c where a, b and c are the numerical coefficients

So, lets try and see;

A.

$5x+4=3x^4-2\\\\=3x^4-5x-2-4\\=3x^4-5x-6\\a=3,b=-5,c=-6$

But due to the fact that in this equation you have x⁴, the equation is not a quadratic equation thus can not be solved using this formula

B

$-x^2+4x+7=-x^2-9\\\\\\=-x^2+x^2+4x+7+9\\=4x+16$

C

$9x+3x^2=14+x-1\\\\\\=3x^2+9x-x-14+1\\\\=3x^2+8x-13\\\\\\a=3,b=8,c=-13\\$

D.

$2x^2+x^2+x=30\\\\\\=3x^2+x-30\\\\\\a=3,b=1,c=-30$

From the checking above, the equations will be C and D

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