Answer:
t= 2.52 hours
Step-by-step explanation:
It is given that for first 30 km, the speed of bicyclist is v km/hour
time taken to cover first 30 km is given by
(
)
for next 17 km the speed of bicyclist is 2 km/hour greater than his original speed
so the speed to cover next 17 km = v+2
time taken to cover next 17 km is given by
![t_{2} =\frac{17}{v+2}](https://tex.z-dn.net/?f=t_%7B2%7D%20%3D%5Cfrac%7B17%7D%7Bv%2B2%7D)
now total time t spent by the bicyclist to cover entire trip is given by
![t=t_{1} +t_{2}](https://tex.z-dn.net/?f=t%3Dt_%7B1%7D%20%2Bt_%7B2%7D)
![t=\frac{30}{v} +\frac{17}{v+2}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B30%7D%7Bv%7D%20%2B%5Cfrac%7B17%7D%7Bv%2B2%7D)
now if v=18 , we have
![t=\frac{30}{18} +\frac{17}{20}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B30%7D%7B18%7D%20%2B%5Cfrac%7B17%7D%7B20%7D)
now to add fractions we make the denominator same
Hence we will find the LCM of 18 and 20
LCM of 18 and 20 = 180
now we need to make both the denominator equal to 180
![t=\frac{30(10)}{18(10)} +\frac{17(9)}{20(9)}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B30%2810%29%7D%7B18%2810%29%7D%20%2B%5Cfrac%7B17%289%29%7D%7B20%289%29%7D)
![t=\frac{300}{180} +\frac{153}{180} =\frac{300+153}{180}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B300%7D%7B180%7D%20%2B%5Cfrac%7B153%7D%7B180%7D%20%3D%5Cfrac%7B300%2B153%7D%7B180%7D)
hours (approx)
Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
<u>Step-by-step explanation:</u>
We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,
Perimeter = 42 inches
⇒ ![2(x+y) = 42\\x+y = 21\\y = 21-x](https://tex.z-dn.net/?f=2%28x%2By%29%20%3D%2042%5C%5Cx%2By%20%3D%2021%5C%5Cy%20%3D%2021-x)
width of printed area = x-3 & length of printed area = y-2:
area = ![length(width)](https://tex.z-dn.net/?f=length%28width%29)
![area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57](https://tex.z-dn.net/?f=area%20%3D%20%28x-3%29%28y-2%29%5C%5Carea%20%3D%20%28x-3%29%2821-x-2%29%5C%5Carea%20%3D%20%28x-3%29%2819-x%29%5C%5Carea%20%3D%20-x%5E%7B2%7D%20%2B%2022x%20-57)
Let's find
:
=
, for area to be maximum
= 0
⇒ ![-2x+22 = 0\\2x =22\\x=11 inches](https://tex.z-dn.net/?f=-2x%2B22%20%3D%200%5C%5C2x%20%3D22%5C%5Cx%3D11%20inches)
And ,
![y = 21-x\\y = 21-11\\y = 10 inches](https://tex.z-dn.net/?f=y%20%3D%2021-x%5C%5Cy%20%3D%2021-11%5C%5Cy%20%3D%2010%20inches)
∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
Add 5x + 5 and that is the bottom of it and the top stays 1
Answer:
2 miles is your answer hope this helps!!!!!!
Step-by-step explanation:
Answer:
The answer would be D+ 38.4 cm
Step-by-step explanation:
You would do 1.6 cm times 24