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Bond [772]
4 years ago
14

The vertices of a triangle are P(2,-4), Q(-5,3), and R(-1,-2). What are the vertices of the image reflected across the y-axis?

Mathematics
2 answers:
erma4kov [3.2K]4 years ago
5 0
I'm assuming this is from the Geometry Semester B Exam for connexus. The answer was C

Tresset [83]4 years ago
4 0
When an object is reflected over the y axis you simply multiply every x variable by -1. The vertices are P(-2,-4), Q(5,3), and R(1,-2)
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A trucks height is 3 meters 35 centimeters. how tall is the truck in millimeters
amid [387]
3 meters = 300 cm
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Each cm is 10mm


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3 years ago
Solve the system of equations. \begin{aligned} &-9y+4x - 20=0 \\\\ &-7y+16x-80=0 \end{aligned} ​ −9y+4x−20=0 −7y+16x−80=
bekas [8.4K]

Answer:

(5 , 0)

Step-by-step explanation:

7 * (−9y+4x−20)=0

9 * (−7y+16x−80)=0

-63y + 28x -140 = 0 ......a

-63y + 144x -720 = 0 .....b

b-a:  116x - 580 = 0

116x = 580

x = 5

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7 0
3 years ago
There’s a button for the pic
Arlecino [84]
A Multiply the input number by 6 because 2 times 6= 12, 6 times 6= 36, 8 times 6= 48, 9 times 6= 54, and 12 times 6= 72.
7 0
3 years ago
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Natalka [10]
It is like
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3 0
4 years ago
Read 2 more answers
Solve:<br><br> (15/x)+(9x-7)/(x+2)=9
hram777 [196]

Answer:x=3

Step-by-step explanation:

D( x )

x+2 = 0

x = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x = 0

x = 0

x in (-oo:-2) U (-2:0) U (0:+oo)

(9*x-7)/(x+2)+15/x = 9 // - 9

(9*x-7)/(x+2)+15/x-9 = 0

(x*(9*x-7))/(x*(x+2))+(15*(x+2))/(x*(x+2))+(-9*x*(x+2))/(x*(x+2)) = 0

x*(9*x-7)+15*(x+2)-9*x*(x+2) = 0

9*x^2-9*x^2+8*x-18*x+30 = 0

30-10*x = 0

(30-10*x)/(x*(x+2)) = 0

(30-10*x)/(x*(x+2)) = 0 // * x*(x+2)

30-10*x = 0

30-10*x = 0 // - 30

-10*x = -30 // : -10

x = -30/(-10)

x = 3

x = 3

3 0
3 years ago
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