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4 years ago

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An appliance dealer sold 40 tv sets during a special sale. Some of the sets were black-and - white models each selling at $119.

The rest were color sets at $319 each. The sale brought in $10,360. How many color sets were sold?

1 answer:

Harman [31]4 years ago

8 0

Answer: 28 color sets were sold

Step-by-step explanation:

Let x represent the number of black-and - white models that were sold.

Let y represent the number of color sets that were sold.

An appliance dealer sold 40 tv sets during a special sale. Some of the sets were black-and - white models while the rest were color sets.. It means that

x + y = 40

Black-and - white models each sold for $119. Color sets sold at $319each. The sale brought in $10,360. It means that

119x + 319y = 10360 - - - - - -- - - - - -1

Substituting x = 40 - y into equation 1, it becomes

119(40 - y) + 319y = 10360

4760 - 119y + 319y = 10360

- 119y + 319y = 10360 - 4760

200y = 5600

y = 5600/200

y = 28

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Step-by-step explanation:

From the question;

Length is 12 cm
Width is 10 cm

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Note that the cross section is the plane of a solid that remains constant through the solid.
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Answer:

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Answer :

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B) The results cannot be a representative of the variation of attractiveness among the population of adult males

Step-by-step explanation:

A ) calculate the Range, variance and standard deviation

The given data = 9, 6, 2, 1, 2, 5, 5, 1, 2, 6, 8, 10, 6, 6, 1, 5, 1, 3, 4, 4, 4, 5, 10, 9, 1, 6

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3 years ago

Help me to answer now ineed this <br> Please...

Vera_Pavlovna [14]

ANSWER TO QUESTION 1

$\frac{\frac{y^2-4}{x^2-9}} {\frac{y-2}{x+3}}$

Let us change middle bar to division sign.

$\frac{y^2-4}{x^2-9}\div \frac{y-2}{x+3}$

We now multiply with the reciprocal of the second fraction

$\frac{y^2-4}{x^2-9}\times \frac{x+3}{y-2}$

We factor the first fraction using difference of two squares.

$\frac{(y-2)(y+2)}{(x-3)(x+3)}\times \frac{x+3}{y-2}$

We cancel common factors.

$\frac{(y+2)}{(x-3)}\times \frac{1}{1}$

This simplifies to

$\frac{(y+2)}{(x-3)}$

ANSWER TO QUESTION 2

$\frac{1+\frac{1}{x}} {\frac{2}{x+3}-\frac{1}{x+2}}$

We change the middle bar to the division sign

$(1+\frac{1}{x}) \div (\frac{2}{x+3}-\frac{1}{x+2})$

We collect LCM to obtain

$(\frac{x+1}{x})\div \frac{2(x+2)-1(x+3)}{(x+3)(x+2)}$

We expand and simplify to obtain,

$(\frac{x+1}{x})\div \frac{2x+4-x-3}{(x+3)(x+2)}$

$(\frac{x+1}{x})\div \frac{x+1}{(x+3)(x+2)}$

We now multiply with the reciprocal,

$(\frac{(x+1)}{x})\times \frac{(x+2)(x+3)}{(x+1)}$

We cancel out common factors to obtain;

$(\frac{1}{x})\times \frac{(x+2)(x+3)}{1}$

This simplifies to;

$\frac{(x+2)(x+3)}{x}$

ANSWER TO QUESTION 3

$\frac{\frac{a-b}{a+b}} {\frac{a+b}{a-b}}$

We rewrite the above expression to obtain;

$\frac{a-b}{a+b}\div {\frac{a+b}{a-b}}$

We now multiply by the reciprocal,

$\frac{a-b}{a+b}\times {\frac{a-b}{a+b}}$

We multiply out to get,

$\frac{(a-b)^2}{(a+b)^2}$

ANSWER T0 QUESTION 4

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We multiply through by the LCM of $(m+1)(m-1)$

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This gives us,

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This simplifies to;

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ANSWER TO QUESTION 5

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We simplify to get,

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Method 1: Simplifying the expression as it is.

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Method 2: Changing the middle bar to a normal division sign.

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We simplify further to get,

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$\frac{19}{20}\div \frac{(37)}{40}$

We now multiply by the reciprocal,

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$\frac{19}{1}\times \frac{2}{37}$

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5 0

3 years ago

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