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irinina [24]
3 years ago
5

The line that passes through the points (9,1) and (5,5) intersects the y-axis at (0,5).

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0
The stament are true I think
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Use a table of function values to approximate an x-value in which the exponential function exceeds the polynomial function. In y
bekas [8.4K]
F(x) = 2^x; h(x) = x^3 + x + 8

Table


x      f(x) =  2^x             h(x) = x^3 + x + 8

0      2^0 = 1                0  + 0 + 8 = 8

1     2^1 = 2                 1^3 + 1 + 8 = 10

2      2^2 = 4                2^3 + 2 + 8 = 8 + 2 + 8 = 18

3      2^3 = 8                3^3  + 3 + 8 = 27 + 3 + 8 = 38

4      2^2 = 16              4^3 + 4 + 8 = 76

10    2^10 = 1024       10^3  +10 + 8 = 1018

 9      2^9 =   512        9^3 + 9 + 8 = 729 + 9 + 8 = 746

Answer: an approximate value of 10
7 0
3 years ago
If she saves 1$ the first week 3$ the season week 9$ the third week how much will she save in 5 weeks
ycow [4]

Based on the numbers we have we can assume that she saves 3 times more each week than the last (1*3=3, 3*3=9).

Following this trend we would multiply the amount she saved the third week ($9) by 3 to get $27 for the fourth week.

Then, we would multiply the amount she saved the fourth week ($27) by 3 to get $81 for the fifth week.

Finally, to figure out how much she saved in the 5 weeks, we need to add each value up to get 1+3+9+27+81= $121 saved in 5 weeks

5 0
3 years ago
Vincent is watching a movie that last one hour and 37 minutes.he has watched 52 minutes so far how many minutes are left in the
Neporo4naja [7]
<h3>given:</h3>

lasts= 1 hour 37 minutes

watched= 52 mins

<h3>to find:</h3>

how many minutes left in the movie.

<h3>solution:</h3>

to find the time left just find the difference.

52 - 37

= 15

60 - 15

= 45

<u>therefore</u><u>,</u><u> </u><u>there's</u><u> </u><u>4</u><u>5</u><u> </u><u>mins</u><u> </u><u>left</u><u> </u><u>in</u><u> </u><u>the</u><u> </u><u>movie</u><u>.</u>

6 0
2 years ago
Read 2 more answers
Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
3 years ago
What single decimal multiplier would you use to increase by 15% followed by a 14% increase?
umka2103 [35]

9514 1404 393

Answer:

  1.311

Step-by-step explanation:

That multiplier is the product of the multipliers for each of the increases:

  (1 +15%)(1 +14%) = 1.15×1.14 = 1.311

5 0
3 years ago
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