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Llana [10]
3 years ago
5

Mark as brainliest!!

Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

After 45 hours the lava reached its maximum distance from the fissure and cooled. How many kilometers was the resulting flood basalt?

Lava from a hot spot flowed out of a fissure at the rate of 0.8 km/h.

B.36

Lava from a hot spot flowed out of a fissure at the rate of 0.8 km/h

How long did it take lava to flow

30 hours

table should look like

12      9.6

30      24

45       36

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(5x 4 – 3x 3 + 6x) – ( 3x 3 + 11x 2 – 8x)
BaLLatris [955]
5x⁴ - 3x³ + 6x) - (3x³ + 11x² - 8x)<span>

</span>Expand the second bracket by multiplying throughout by -1
5x⁴ - 3x³ + 6x - <span>3x³ - 11x² + 8x
</span>
Group like terms and simplify 
5x⁴ - 3x³ - 3x³ - 11x² + 6x <span>+ 8x

</span>5x⁴ - 6x³ - <span>11x² + 14x</span>
6 0
3 years ago
Read 2 more answers
A rectangle has two different side lengths: One is (4p-5) inches. The other is (3p+2) inches. Find the perimeter of the rectangl
Anika [276]

The perimeter of rectangle is 14p-6.

Step-by-step explanation:

Given,

One side of rectangle = 4p-5  inches

Length of other side = 3p+2 inches

Perimeter of rectangle = 2( Length of one side + Length of other side)

Perimeter = 2(4p-5+3p+2)\\Perimeter = 2(7p-3)\\Perimeter = 14p-6

The perimeter of rectangle is 14p-6.

Keywords: rectangle, perimeter

Learn more about rectangle at:

  • brainly.com/question/10552347
  • brainly.com/question/10570041

#LearnwithBrainly

7 0
3 years ago
(3+5)x7-[10+(45-15)\5]
Gelneren [198K]
Use\ PEMDAS\\\\(3+5)\times7-[10+\frac{(45-15)}{5}]=(8)\times7-(10+\frac{30}{5})\\\\=56-(10+6)=56-16=\boxed{\boxed{40}}
7 0
3 years ago
Calculate pt3 such that a line from pt1 to pt3 is perpendicular to the line from pt1 to pt2, and the distance between pt1 and pt
Leni [432]
Let the point_1 = p₁ = (1,4)
and      point_2 = p₂ = (-2,1)
and      Point_3 = p₃ = (x,y)

The line from point_1 to point_2 is L₁ and has slope = m₁
The line from point_1 to point_3 is L₂ and has slope = m₂
m₁ = Δy/Δx = (1-4)/(-2-1) = 1
m₂ = Δy/Δx = (y-4)/(x-1)
L₁⊥L₂ ⇒⇒⇒⇒ m₁ * m₂ = -1
∴ (y-4)/(x-1) = -1 ⇒⇒⇒ (y-4)= -(x-1)
(y-4) = (1-x) ⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒⇒ equation (1)

The distance from point_1 to point_2 is d₁
The distance from point_1 to point_3 is d₂
d = \sqrt{Δx^2+Δy^2}
d₁ = \sqrt{(-2-1)^2+(1-4)^2}
d₂ = \sqrt{(x-1)^2+(y-4)^2}
d₁ = d₂
∴ \sqrt{(-2-1)^2+(1-4)^2} = \sqrt{(x-1)^2+(y-4)^2} ⇒⇒ eliminating the root
∴(-2-1)²+(1-4)² = (x-1)²+(y-4)²
 (x-1)²+(y-4)² = 18
from equatoin (1)  y-4 = 1-x
∴(x-1)²+(1-x)² = 18            ⇒⇒⇒⇒⇒ note: (1-x)² = (x-1)²
2 (x-1)² = 18
(x-1)² = 9
x-1 = \pm \sqrt{9} = \pm 3
∴ x = 4 or x = -2
∴ y = 1 or y = 7

Point_3 = (4,1)  or  (-2,7)












8 0
4 years ago
What is the value of x?<br><br><br><br> 3x−8=(8x+4<br> -----<br> 2
stepladder [879]

3x-8 = 8x+4

subtract 3x from each side

-8 = 5x+4

 subtract 4 from each side

-12 = 5x

divide -12 by 5 to get x

x = -12/5 = -2.4

3 0
3 years ago
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