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igomit [66]
3 years ago
10

Jackie received 78% of the votes in an election. in a random sample of 40 eligible voters, 28 said they voted for jackie. which

answer represents p and p?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0
The answer to this question is C since <span>78% of the votes in an election. in a random sample of 40 eligible voters, 28 said they voted for jackie.</span>
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-2(21/4)+-2(13/4) what is the answer
sergij07 [2.7K]

Answer:

-17

Step-by-step explanation:

-2(21/4)-2(13/4)

-(21/2)-26/4

-21/2-26/4

-42/4-26/4

-68/4

-17

4 0
3 years ago
Read 2 more answers
what is the equation of the line, in point-slope form, that passes through the given point and has the given slope ? point (7,3)
Maru [420]

Answer:

y-3 = 4/7(x-7)

Step-by-step explanation:

Point slope form is

y-y1 = m(x-x1)

We know the slope (4/7)

and a point (7,3)

Lets substitute into the equation

y-3 = 4/7(x-7)

6 0
4 years ago
Amanda plans on going to the amusement park this Friday. It costs $25.00 to
Vera_Pavlovna [14]

Answer:

$36.25

Step-by-step explanation:

To enter the park, Amanda pays 25 dollars.

+$25

It costs 1.25 for every ride that Amanda goes on.

Since we don't know the number of rides Amanda goes on, we will add a variable to represent the number of rides.

1.25x

Then, the passage says that Amanda goes on 9 rides. So, substitute 9 for x.

Equation: 25+1.25(9)

Then solve:

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4 0
3 years ago
Is (-1,4) a solution of the inequality y&lt;2x+5?
Sveta_85 [38]
Let's plug x= -1, y= 4 in the inequation, we have:
4< 2*(-1)+5
⇒ 4< -2+5
⇒ 4< 3 (false)

Therefore, (-1,4) is not a solution of the inequation y<2x+5~
6 0
3 years ago
Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,
Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}

4 0
3 years ago
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