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Lera25 [3.4K]
2 years ago
12

Find the area of the shape below, giving your answer to 1 decimal place

Mathematics
1 answer:
STALIN [3.7K]2 years ago
5 0

Answer:

Total area is 198.6cm²

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes.

Step one

From the given figure the two semi circles left and right can be resolved as a whole (a complete circle) with diameter d 10cm

Radius r = 10/2= 5cm

Area of circle A= πr²

A= 3.142*5²

A= 3.142*25

A= 78.55

A= 78.6cm²

Step two

The remaining part of the shape is a rectangle with length (22-10)= 12cm

I.e the 10 is as a result of the radius of the two semi circles = r+r= 5+5=10

The rectangle has a width of 10cm

Area of rectangle A=12*10= 120cm²

Hence the total surface area of the shape

Total area = 120+78.6

Total area = 198.6cm²

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Which is the area of a rectangle with a length of 21 feet and a width of 15 feet
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315 ft^2

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Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.
dmitriy555 [2]

see the attached figure to better understand the problem

we have that

cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

cos (A)=(AC/AB)\\AC=AB*cos(A)

substitute the values in the formula

AC=12*(1/5)\\ AC=2.4\ units

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}

substitute the values

BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units

Step 3  

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

BD^{2} =DC^{2}+BC^{2}

substitute the values  

BD^{2} =2^{2}+11.76^{2}

BD=11.93\ units

therefore

<u>the answer is</u>

the length of BD is 11.93 units

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