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Ratling [72]
3 years ago
13

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s0t)(-7)?

Mathematics
1 answer:
Juliette [100K]3 years ago
3 0

Answer:

The answer would be -439

Step-by-step explanation:

To find this, start by finding t(-7)

t(x) = 3x

t(-7) = 3(-7)

t(-7) = -21

Now that we have this answer, we input it into the s(x) equation.

s(x) = 2 - x^2

s(-21) = 2 - (-21)^2

s(-21) = 2 - 441

s(-21) = -439

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faust18 [17]
Use this property of logarithms:

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Your equation transforms into:

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Now, you have to apply the definition of a logarithm to express the equation in exponential form:

\dfrac{x^2+3x}{x+5} = 4^1

In case you don't remember, this is the definition of a logarithm:

\log_b x = y \iff b^y = x

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Finally, solve the rational equation:

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5 0
3 years ago
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Therefore:
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4 0
3 years ago
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