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Juliette [100K]
2 years ago
15

Find the slope of a line that goes through the two points (-1, 1) and (-3, -7).

Mathematics
2 answers:
Natasha2012 [34]2 years ago
8 0

Answer:

4

Step-by-step explanation:

\frac{-7 - 1}{-3-(-1)} = \frac{-8}{-2} = 4

il63 [147K]2 years ago
3 0

Answer:

the slope of the line is <u>4</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>working</u><u> </u><u>is</u><u> </u>in the attached picture

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Which numbers make a true statement when placed in the box? 7.902 &gt; Select each correct answer.
Zanzabum
The answer is b, I’m not saying it’s true but just predicting xoxoox
6 0
2 years ago
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Mystery Boxes: Breakout Rooms
ollegr [7]

Answer:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

Step-by-step explanation:

Given

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {[ \ ]} \\ \end{array}

Required

Fill in the box

From the question, the range is:

Range = 60

Range is calculated as:

Range =  Highest - Least

From the box, we have:

Least = 1

So:

60 = Highest  - 1

Highest = 60 +1

Highest = 61

The box, becomes:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question:

IQR = 20 --- interquartile range

This is calculated as:

IQR = Q_3 - Q_1

Q_3 is the median of the upper half while Q_1 is the median of the lower half.

So, we need to split the given boxes into two equal halves (7 each)

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {[ \ ] } & {15} & {18}& {[ \ ] } \\ \end{array}

<u>Upper half</u>

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

The quartile is calculated by calculating the median for each of the above halves is calculated as:

Median = \frac{N + 1}{2}th

Where N = 7

So, we have:

Median = \frac{7 + 1}{2}th = \frac{8}{2}th = 4th

So,

Q_3 = 4th item of the upper halves

Q_1= 4th item of the lower halves

From the upper halves

<u></u>\begin{array}{ccccccc}{[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}<u></u>

<u></u>

We have:

Q_3 = 32

Q_1 can not be determined from the lower halves because the 4th item is missing.

So, we make use of:

IQR = Q_3 - Q_1

Where Q_3 = 32 and IQR = 20

So:

20 = 32 - Q_1

Q_1 = 32 - 20

Q_1 = 12

So, the lower half becomes:

<u>Lower half:</u>

\begin{array}{ccccccc}{1} & {[ \ ]} & {4} & {12 } & {15} & {18}& {[ \ ] } \\ \end{array}

From this, the updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {[ \ ] } & {[ \ ]} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question, the median is:

Median = 22 and N = 14

To calculate the median, we make use of:

Median = \frac{N + 1}{2}th

Median = \frac{14 + 1}{2}th

Median = \frac{15}{2}th

Median = 7.5th

This means that, the median is the average of the 7th and 8th items.

The 7th and 8th items are blanks.

However, from the question; the mode is:

Mode = 18

Since the values of the box are in increasing order and the average of 18 and 18 do not equal 22 (i.e. the median), then the 7th item is:

7th = 18

The 8th item is calculated as thus:

Median = \frac{1}{2}(7th + 8th)

22= \frac{1}{2}(18 + 8th)

Multiply through by 2

44 = 18 + 8th

8th = 44 - 18

8th = 26

The updated values of the box is:

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

From the question.

Mean = 26

Mean is calculated as:

Mean = \frac{\sum x}{n}

So, we have:

26= \frac{1 + 2nd + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 12th + 58 + 61}{14}

Collect like terms

26= \frac{ 2nd + 12th+1 + 4 + 12 + 15 + 18 + 18 + 26 + 29 + 30 + 32 + 58 + 61}{14}

26= \frac{ 2nd + 12th+304}{14}

Multiply through by 14

14 * 26= 2nd + 12th+304

364= 2nd + 12th+304

This gives:

2nd + 12th = 364 - 304

2nd + 12th = 60

From the updated box,

\begin{array}{ccccccccccccccc}{1} & {[ \ ]} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {[ \ ]} & {58} & {61} \\ \end{array}

We know that:

<em>The 2nd value can only be either 2 or 3</em>

<em>The 12th value can take any of the range 33 to 57</em>

Of these values, the only possible values of 2nd and 12th that give a sum of 60 are:

2nd = 3

12th = 57

i.e.

2nd + 12th = 60

3 + 57 = 60

So, the complete box is:

\begin{array}{ccccccccccccccc}{1} & {3} & {4} & {12} & {15} & {18}& {18 } & {26} & {29} & {30} & {32} & {57} & {58} & {61} \\ \end{array}

6 0
2 years ago
I need help What is the surface area of the following figure? A 168 B 192 PLEASE HELP
Juliette [100K]

Answer:

<u>305 in^2</u>

Step-by-step explanation:

First step is always to break up the problem into parts and write out our formulas- in this case, let's solve the easier part first, the bottom rectangular box type shape.

Area of a square or rectangle: A= length * height

Area of a triangle: A = 1/2 * length * height

Each side is 6x2, making each side 12 in^2, times four sides equals 48 in^2

The box also has a bottom, with dimensions of 6x6, equaling 36 in^2. <em>be careful not to include the top, it may be included in this part of the problem that we're splitting up, but it's not in the actual figure</em>.

Next up is the top portion- let's calculate the two triangular sides first. again, A=(1/2)l*h . so, these triangles are (1/2) * 5 * 4 , or 10 in^2 . With two triangular sides that's 20 in^2 total.

And now we only have two sides left, the rectangular parts of the triangular prism. They have a dimension of 5*6, equalling 30, and with two sides its a total of 60 in^2.

All of these sides can be added together:

48 + 36 + 20 + 60 = 305 in^2

3 0
3 years ago
Read 2 more answers
The Colonel spots a campfire at a bearing N 59∘59∘ E from his current position. Sarge, who is positioned 242 feet due east of th
Rashid [163]

Answer:

i. Colonel is about 201 feet away from the fire.

ii. Sarge is about 125 feet away from the fire.

Step-by-step explanation:

Let the Colonel's location be represented by A, the Sarge's by B and that of campfire by C.

The total angle at the campfire from both the Colonel and Sarge = 59^{0} + 34^{0}

                                           = 93^{0}

Thus,

<CAB = 90^{0} - 59^{0} = 31^{0}

<CBA = 90^{0} - 34^{0} = 56^{0}

Sine rule states;

\frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C}

i. Colonel's distance from the campfire (b), can be determined by applying the sine rule;

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{b}{Sin 56^{0} } = \frac{242}{Sin 93^{0} }

\frac{b}{0.8290} = \frac{242}{0.9986}

cross multiply,

b = \frac{0.8290*242}{0.9986}

  = 200.8993

Colonel is about 201 feet away from the fire.

ii. Sarge's distance from the campfire (a), can be determined by applying the sine rule;

\frac{a}{Sin A} = \frac{c}{Sin C}

\frac{a}{Sin 31^{0} } = \frac{242}{Sin 93^{0} }

\frac{a}{0.5150} = \frac{242}{0.9986}

cross multiply,

a = \frac{0.5150*242}{0.9986}

  = 124.8073

Sarge is about 125 feet away from the fire.

8 0
3 years ago
81 is 45% of what number
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81 is 45% of 180, all you do is divide 81 by .45 and boom there you go
8 0
3 years ago
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