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Nana76 [90]
3 years ago
15

Which of the following in an identity?

Mathematics
1 answer:
sammy [17]3 years ago
5 0
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
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Answer:

Step-by-step explanation:

Given that a researcher is trying to decide how many people to survey.

We have confidence intervals are intervals with middle value as the mean and on either side margin of error.

Confidence interval = Mean ± Margin of error

Thus confidence interval width depends on margin of error.

Margin of error = Critical value *\frac{\sigma}{\sqrt{n} }

Thus for the same confidence level and std deviation we find margin of error is inversely proportional to square root of sample size.

Hence for small n we get wide intervals.

So if sample size = 300, the researcher will get wider confidence interval

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3 years ago
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irakobra [83]

Answer:

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Step-by-step explanation:

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Answer:

Please read all of this! Underlined things are the answers. The area of the entire circle is 19.625

Step-by-step explanation:

(This is a circle so the middle line is the diameter. According to the attachment, the diameter is 5 cm. To find the area, we have to multiply π and the radius squared. The radius is half of the diameter.

5 ÷ 2 = 2.5

2.5² = 6.25

π = 3.14

3.14 x 6.25 = 19.625)

Ignore the top I just realized what I'm supposed to do but I left it there just in case you need help!

<u>The right and left shaded regions areas are 6.28 each.</u>

4 ÷ 2 = 2

2² = 4

3.14 x 4 = 12.56

Since this is a semi circle, we cut it in half.

12.56 ÷ 2 = 6.28

To find the top and bottom shaded region's areas, repeat the same steps.

3 ÷ 2 = 1.5

1.5² = 2.25

3.14 x 2.25 = 7.065

7.065 ÷ 2 = 3.5325

<u>The areas of the the top and bottom shaded regions are 3.5325 each.</u>

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Answer:

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Step-by-step explanation:

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3 years ago
For* 15-16 find the number of sides if a polygon has the given measure for each interior angle,
salantis [7]

Answer:

15. d) 36

16. b) 20

17. d) 180

18. b) 50

19. c) 360

20. b) 60

Step-by-step explanation:

To find the number of sides a polygon has giving an interior angle, use the equation:

(number of sides - 2)*180/(number of sides) = measure of interior angle

<em>15. </em>(n = number of sides)

((n-2)*180)/n = 170

180n-360 = 170n

10n = 360

n = 36 (d)

<em>16.</em> (n = number of sides)

((n-2)*180)/n = 162

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<em>17.</em> The sum of the interior angles of a triangle is always 180 (d)

<em>18.</em> 180-60-70 = 50 (b)

<em>19.</em> The sum of the interior angles of a quadrilateral is always 360 (c)

<em>20.</em> 360-120-90-90 = 60 (b)

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