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Nana76 [90]
2 years ago
15

Which of the following in an identity?

Mathematics
1 answer:
sammy [17]2 years ago
5 0
By "which is an identity" they just mean "which trigonometric equation is true?"

What you have to do is take one of these and sort it out to an identity you know is true, or...

*FYI: You can always test identites like this:
Use the short angle of a 3-4-5 triangle, which would have these trig ratios:
sinx = 3/5    cscx = 5/3
cosx = 4/5   secx = 5/4
tanx = 4/3    cotx = 3/4
Then just plug them in and see if it works. If it doesn't, it can't be an identity!

Let's start with c, just because it seems obvious.
The Pythagorean identity states that sin²x + cos²x = 1, so this same statement with a minus is obviously not true.

Next would be d. csc²x + cot²x = 1 is not true because of a similar Pythagorean identity 1 + cot²x = csc²x. (if you need help remembering these identites, do yourslef a favor and search up the Magic Hexagon.)

Next is b. Here we have (cscx + cotx)² = 1. Let's take the square root of each side...cscx + cotx = 1. Now you should be able to see why this can't work as a Pythagorean Identity. There's always that test we can do for verification...5/3 + 3/4 ≠ 1, nor is (5/3 +  3/4)².

By process of elimination, a must be true. You can test w/ our example ratios:
sin²xsec²x+1 = tan²xcsc²x
(3/5)²(5/4)²+1 = (4/5)²(5/3)²
(9/25)(25/16)+1 = (16/25)(25/9)
(225/400)+1 = (400/225)
(9/16)+1 = (16/9)
(81/144)+1 = (256/144)
(81/144)+(144/144) = (256/144)
(256/144) = (256/144)
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Determine the equation of g(x) that results from translating the function f(x)=x^2+9 upward 10 units.
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The simple/ <span>common sense method:
</span>The typical lay out of a quadratic equation is ax^2+bx+c 
'c' represents where the line crosses the 'y' axis. 
The equation is only translated in the 'y' (upwards/downwards) direction, therefore only the 'c' component of the equation is going to change. 
A translation upwards of 10 units means that the line will cross the 'y' axis 10 places higher. 
9+10=19, 
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<span>
<span>The most complicated/thorough method: 
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ax^2+bx+c 
a=1, b=0, c=9
Find the vertex (the highest of lowest point) of f(x). 
Use the -b/2a formula to find the 'x' coordinate of your vertex.. 
x= -0/2*1, your x coordinate is therefore 0. 
substitute your x coordinate into your equation to find your y coordinate.. 
y= 0^2+0+9
y=9. 
Your coordinates of your vertex f(x) are therefore <u>(0,9) </u>
The translation of upward 10 units means that the y coordinate of the vertex will increase by 10. The coordinates of the vertex g(x)  are therefore: 
<u>(0, 19) </u>
substitute your vertex's y coordinate into f(x) 
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19=0+c
c=19
therefore <u>g(x)=x^2+19</u>

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3 years ago
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In AIJK, i = 270 cm, j = 170 cm and _K=122°. Find the area of AIJK, to the
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Answer:

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Step-by-step explanation:

The area is given by the formula ...

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Filling in the values, we find the area to be ...

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The answer is C.

Step-by-step explanation:

No because the graph fails the vertical line test.

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