Answer:
a.

Step-by-step explanation:
Answer:
There are 16 Oak tree in the forest.
Step-by-step explanation:
Given: There are 4 Oak tree on every 10 pine trees.
There are total 24 more pine tree than Oak tree.
Using the ratio of trees to find the number of trees.
Lets assume there are total number of Oak tree be "x".
∴ Total number of Pine trees will be 
We know the ratio of Oak to Pine tree is 4:10 or 
⇒
Multiplying both side by 
⇒ 
Using distributive property of multiplication, distributing 4 with x and 24.
⇒ 
Multiplying both side by 10
⇒ 
subtracting both side by 4x
⇒ 
dividing both side by 6
⇒
∴ 
Hence, There are 16 Oak trees in the forest.
<span> The lower and upper bounds of the confidence intervals must be equally distanced from the mean
so it will be
</span><span>70.9 - 73.1
</span>hope it helps
Find all the prime factors of the three numbers. pick up the common factors, ONCE, then pick up the non-common factors one by one, multiply the factors, the product is the least common factor.
example: the least common multiple of 6, 8, and 15
6=2*3
8=2*2*2
15=3*5
Note: do not write 8 into 4*2, because 4 is not a prime number. you have to break the number down to prime factors only.
Notice that 6 and 8 have a common factor 2, so pick up the 2;
6 and 15 have a common factor of 3, so pick up the 3.
those are the only two shared factors, so 2×3
now pick up whatever is not shared:
the two 2s for 8 and the 5 for 15 is not shared, add 2, 2, and 5 to the multiplication: 2×3×2×2×5=120
120 is the least common multiples of 6,8, and 15
this is basically how it is done. I believe you can explain better in your own words.
Answer:
The answer is "0.765 and 0.2353".
Step-by-step explanation:
Please find the complete question in the attached file.
In point a:
P(a substantive term only)
P(major health insurance only) 
P(both)
P(renewal) =P(insurance and renewal term only)+P (substantial and renewable health insurance only)+P (both and renew)

In point b:
In reality, the probability of having both life and major medical insurance provided the policyholder would renew next year

