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Bumek [7]
3 years ago
8

Write the umber 10.5 in the form a/b

Mathematics
2 answers:
Allushta [10]3 years ago
5 0

Answer:

\frac{21}{2}

Step-by-step explanation:

The given number is 10.5.

We need to write the given number in the form of a/b.

Multiply an divide the given number by 10 to remove the decimal.

10.5\times \frac{10}{10}

\frac{10.5\times 10}{10}

\frac{105}{10}

It can be written as

\frac{5\times 21}{5\times 2}

Now cancel out common factors.

\frac{21}{5}

Therefore, the fraction form of given number is \frac{21}{2}.

Dafna11 [192]3 years ago
3 0
The umber  10.5  can be written as

==>  21 / 2

==>  42 / 4

==>  63 / 6

==>  84 / 8

==>  105 / 10

and many, many other ways.

They ALL have the same value.

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Suppose<br> cos(π/2−x) =3/5, cos x =4/5<br> find sin, tan, csc, sec, cot
Pani-rosa [81]
Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
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Answer:

Average rate of change: -3

Step-by-step explanation:

<u>Remember:</u>

The average rate of change of a function over an interval [a,b] is \frac{f(b)-f(a)}{b-a}

<u>Given:</u>

[a,b]=[1,7]

f(b)=f(7)

f(a)=f(1)

<u>Calculation:</u>

f(b)=f(7)=-(7)^2+5(7)+14=-49+35+14=-49+49=0

f(a)=f(1)=-(1)^2+5(1)+14=-1+5+14=4+14=18

\frac{f(b)-f(a)}{b-a}=\frac{0-18}{7-1}=\frac{-18}{6}=-3

Therefore, the average rate of change of the function g(x)=-x^2+5x+14 over the interval 1\leq x\leq7 is -3.

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It states "the product of any number and zero is zero". Even if there are more than one multiplier - it is still 0.

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