If the amount of time is x seconds, then 15*x is the amount ran by one child and 6*x is the amount ran for the other child due to that they add 15 or 6 feet for each second. In addition, since they are 450 feet apart, 15x+6x=450=21x. Dividing both sides by 21, we get x=around 21.4 seconds. Since the mother is always between them, when those two meet is when the three meet. Therefore, she runs 20* around 21.4= around 428.57 feet
Simple interest I= prt. 1,250 x 4.5 x 5 equals $28,125
EF = 12
Step-by-step explanation:
Step 1 :
The square of side 18 in is divided into 3 parts of equal area by the polygonal chain
So we have
Area of the figure ABCE = Area of the figure AECF = Area of the figure AFCD
Step 2 :
Area of figure ABCE is Area of the triangle AME + Area of the trapezium EMBC
Area of triangle AME = 1/2(ME )(AM) where ME is the base and AM = 9 is the height of the triangle ( AM = 9 since M is the midpoint of AB)
Area of triangle AME = 1/2(ME )9 = 9/2(ME)
Area of the trapezium EMBC = 1/2(ME +BC)(MB) Where ME and BC are the 2 parallel sides and MB is the distance between them
Area of the trapezium EMBC = 1/2(ME+18)9 = 9/2(ME+18)
Therefore
Area of figure ABCE = 9/2(ME) + 9/2(ME+18)
= 9/2(ME +ME+18)
But we know that the area of this figure is 1/3 of the area of the square = 1/3(18*18) = 108
So, 9/2(ME +ME+18) = 108 => 2 ME + 18 = 24 = > ME = 3
Step 3 :
Using the same procedure as above we get, FN = 3
Also we have
ME + EF + FN = 18 ( side of the square)
3 + EF + 3 = 18 => EF = 12
I did the PEMDAS method (P= parentheses, E= exponents, M= multiplication, D = Division, A= addition, S = subtraction.)
First I did what’s inside the parentheses, (6x2) and got 12.
Then I divided 16 by 22 and received 0.72.
I added 0.72 with 12 and the result was 12.72.
Last step was to subtract 12.72 - 8 and that equals 4.72
Answer:
<em>x= -6</em>
Step-by-step explanation:
so i'm thinking 1 solution.
<u><em>(let me know if i'm wrong)</em></u>
