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3 years ago

[4-2]-10=1 solve the equation

Mathematics

1 answer:

a_sh-v [17]3 years ago

3 0

I think the answer is -20

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I need help. Basically, I need to figure out the dependent and independent value of a function.

Rama09 [41]

Answer:

x = log(y/4)/log(1.0256)
your answer for y=12 is correct

Step-by-step explanation:

The question is asking you to solve ...

y = f(x)

for x. (In other words, find the inverse function.)

You already did this using a constant for y. Do the same thing with y instead of the constant.

y = 4(1.0256^x)

y/4 = 1.0256^x . . . . . . . divide by 4

log(y/4) = x·log(1.0256) . . . . . take logs

log(y/4)/log(1.0256) = x . . . . . divide by the coefficient of x

Now, you have a model for x in terms of y, which is what the question is asking for.

x = log(y/4)/log(1.0256) . . . . . . . exact expression

When y=12, this is ...

x = log(12/4)/log(1.0256) ≈ 43.46 . . . . weeks

_____

This is a linear equation in log(y), so can be written as such:

x = 91.0912·log(y) -54.8424 . . . . . approximate expression

6 0

3 years ago

Cole has already taken 7 quizzes during past quarters, and he expects to have 1 quiz during each week of this quarter. Write an

san4es73 [151]

Answer:

y = x + 7

Step-by-step explanation:

x = number of weeks

y = the total number of quizzes y.

<em>Cole has already taken 7 quizzes = </em>+ 7

<em>he expects to have 1 quiz during each week of this quarter = </em>1x

y = 1x + 7

y = x + 7

7 0

3 years ago

Factors of 64a3 - 343b 3 are

bearhunter [10]

$\huge\mathfrak\green{Constant}$

Constant is the number that cannot change the value

Im not sure..but you can copy it

8 0

3 years ago

Conditional Probability

trapecia [35]

To solve for P(QIR) we use the formula:
P(QIR)=[P(Q∩R)]/P(R)
But from the diagram:
P(Q∩R)=3/22
P(R)=7/22
hence
P(QIR)=3/22÷7/22=3/7

3 0

4 years ago

F(x) = cot x PRE CALC HELP PLS?!

alisha [4.7K]

Check the picture below.

is it even? well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.

does it have a zero at x = 0? well, just look at the graph, is the line touching the x-axis at 0? nope.

does it have an asymptote at 0? well, surely you can see it right there.

8 0

3 years ago