<span>Randomly generate an integer from 1 to 7 two times, and the probability is 1/7 ^2
This is the </span><span>statement that best describes the use of a simulation to predict the probability that two randomly chosen people will both have their birthdays on a Monday.
There are 7 days in a week, so there are 7 choices but only 1 Monday. So, 1/7 is the probability that a person's birthday falls on a Monday.
1st person asked will have 1/7 probability.
2nd person asked will also have 1/7 probability
So, (1/7)</span>² is the probability that both persons will have their birthdays on a Monday.
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible
rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
![\sqrt[3]{80}=2\sqrt[3]{10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D2%5Csqrt%5B3%5D%7B10%7D)
He didn't follow the order the instructions were given to him
The Right expression is:
x-3x10-13
Steps to solve:
1/2hb = d²
~Divide 1/2h to both sides
b = 2d²/h
Best of Luck!
