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3 years ago

CAN SOMEONE PLEASE HELP Simplify (6 1/4)^4

Mathematics

1 answer:

Bond [772]3 years ago

8 0

The answer is 6.

EXPLANATION

All you have to do is to distribute the exponent outside of the parentheses to the constant inside.

That is,

$= ( {6}^{ \frac{1}{4} } )^{4} \\ = {6}^{ \frac{4}{4} } \\ = 6^{1} \\ = 6$

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Expressions with and without Parentheses mutation and on See More

dexar [7]

Answer:

Step-by-step explanation:

each part makes how you can show by what to do on mathematics by fractions and unit fractions with multiplication.

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3 years ago

If anyone is good at math and likes to help someone that is not good with it I will give you brainliest

hammer [34]

Answer:

1st pic answer:

Slope= -3

Parallel slope= -3

Perpendicular slope = 1/3

2nd pic answers:

1 and 2 are parallel

1 and 3 are perpendicular

2 and 3 are perpendicular

Step-by-step explanation:

To find the slope in your first equation (6x+2y=1) you need to get y alone so that your equation will be in slope-intercept form (y=mx+b).

6x+2y=1 Start by subtracting the 6x over to the other side.

-6x -6x

2y= -6x+1 Next divide by 2 to get y completely alone.

$\frac{2y}{2} =\frac{-6x}{2}+\frac{1}{2}$

y= -3x+1/2

So to answer the first part your slope is -3. Parallel slope would be the same as your regular slope. Perpendicular would be the opposite, so that means you have to flip it and change the sign.

-3 flipped is -1/3

if you change the sign it becomes positive giving you 1/3

Part 2

Your first step would be to get all the equations into the slope-intercept form (y=mx+b). The second one is already in the form so we only need to change 1 and 3.

3y=5x+2 To get y alone you need to divide everything by 3.

$\frac{3y}{3}=\frac{5x}{3} +\frac{2}{3}$

y=5/3x+2/3 Before we work on equation 3 we can go ahead and compare equations 1 and 2.

1: y= $\frac{5x}{3} +\frac{2}{3}$

2: y= $\frac{5x}{3} +7$ Since 1 and 2 have the same slope they would be parallel.

Now to change equation 3.

6x+10y=8 Start by subtracting the 6x over to the other side.

-6x -6x

10y=-6x+8 Now divide everything by 10 to get y alone.

$\frac{10y}{10}=\frac{-6x}{10} +\frac{8}{10}$

y=-6x/10+8/10 Now we need to simplify the fractions using common factors. I'm going to use 2 for both equations, so you take -6 and 10 both divided by 2, which gives you -3 and 5(-3x/5). Now do the same with the other fraction. 8 and 10 divided by 2 gives us 4 and 5 (4/5)

3: y= $\frac{-3x}{5}+\frac{4}{5}$

2: y= $\frac{5x}{3} +7$

1: y= $\frac{5x}{3} +\frac{2}{3}$

Since three has an opposite slope of both 1 and 2 it would be perpendicular to both.

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3 years ago

F(x) = 3x -6 What is 7 times f(x)

Alina [70]

Answer:

21x - 42, see below :)

Step-by-step explanation:

Hello!

We know that f(x) is equal to 3x - 6

We want to know what 7 * f(x) is so we should first substitute f(x) for 3x - 6

7 * f(x)

7(3x-6)

We use distributive property to open the parenthesis:

7 * 3x + 7 * -6

21x - 42

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3 years ago

Read 2 more answers

Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container ha

Fittoniya [83]

Answer:

"A is smaller"

Step-by-step explanation:

The full question is attached.

Surface area of cylinder:

The formula is $SA=2\pi r^2 + 2\pi r h$

where r is the radius and h is the height

Here, radius would be 30 since balls have diameter 60 and radius is half of that.

Also height is the diameter of 4 balls line-by-line, so height is 60*4 = 240

Now, plugging into the formula, we get:

$SA=2\pi r^2 + 2\pi r h\\SA=2\pi (30)^2 + 2\pi (30) (240)\\SA=50,868$

Surface Area of rectangular prism:

The surface area of rectangular prism is the area of all the rectangular surfaces (6 of them).

Area of top and bottom = (60+60)*(60+60) * 2 = 120*120 * 2 = 28,800

Area of 2 sides = 2 * (60*120) = 14,400

Area of front and back = 2 * (60*120) = 14,400

Total Surface Area = 28,800 + 14,400 + 14,400 = 57,600

Thus, cylinder has smaller surface area.

"A is smaller"

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3 years ago

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Is college Algebra hard ?

Degger [83]

It depends on what level of classes you take, but algebra classes in college do tend to be harder than algebra classes in high school or middle school.

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2 years ago