All categories

4 years ago

on the stock exchange, 100 shares of pizzazz corp. stock are selling $425. how many shares can be purchased for $1000?

Mathematics

1 answer:

Natali5045456 [20]4 years ago

6 0

Answer:

235.29 shares can be purchased for $1000.

Step-by-step explanation:

On the stock exchange, 100 shares of pizzazz corp. stock are selling $425

We have to determine how many shares can be purchased for $1000?

The price of 100 shares = $425

The price of 1 share = 425/100 = $4.25

Now, It is very easy to calculate the number of shares can be purchased for $1000.

All you have to do is to divide by 1000 by 4.25.

i.e. 1000/4.25 = 235.29 shares

Therefore, 235.29 shares can be purchased for $1000.

You might be interested in

First right gets brainliest:)

Jet001 [13]

First equation: x=-y+8
Second equation: on the picture

4 0

3 years ago

Solve the equation for y -2x+y=11

boyakko [2]

Hi Dezariaspencer

All we have to do is simply add 2x to both sides and we have our answer.

Answer: y = 11 + 2x.

Thank you for asking your question, have a good day.

3 0

4 years ago

Read 2 more answers

These scatterplots represent the monthly sales and advertising costs of a company. Which trend line is the best fit for the data

Lunna [17]

Answer:

Option D

Step-by-step explanation

I did the assignment

8 0

3 years ago

Read 2 more answers

What is the area of this triangle?

Delicious77 [7]

If 2 plus 2 is four... then what the hell is this?

8 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers